K.E. = 1/2 mv²
K.E. is directly proportional to v^2
So, when K.E. increase by 2, K.E. increase by root. 2
v' = 1.41v
original v value was 3 so, final would be:
v' = 1.41*3 = 4.23
After round-off to it's tenth value, it will be:
v' = 4.2
So, option B is your answer!
Hope this helps!
Answer:
100,800 Jkg
The heat that is used to change the state of a mater is called latent heat.
In this case it is converting ice to water and it is called latent heat of fusion.
It is given by:
Heat = mc
where m is the mass of ice and l is the specific latent heat of fusion of ice.
l = 0.336 MJ
Heat = 0.3 × 0.336 MJ
= 0.3 × 0.336 × 10⁶
= 100,800 Jkg
Answer:
450 joules ; 450 joules ; 45.9 m
Explanation:
Given that :
Initial Velocity, u = 30m/s
Mass, m = 1 kg
Kinetic Energy of ball (KE) = 0.5mu²
K. E = 0.5 * 1 * 30^2
K.E = 0.5 * 900
K.E = 450 Joules
B.) Potential Energy (P. E)
P. E = mgh
At the highest point, all kinetic energy has would have become potential energy, hence
K. E = P. E = 450 Joules
C) Height of the ball :
From ; P. E = mgh
Where ; g = acceleration due to gravity = 9.8m/s² ; h = height
450 = 1 * 9.8 * h
450 = 9.8h
h = 450 / 9.8
h = 45.918
h = 45.9 m