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natta225 [31]
3 years ago
12

Suppose that a spring with a larger spring constant was used in this same apparatus. If a given mass were rotated at the same ra

dius at which it had been rotated with the original spring, would the new period of rotation using the new spring be greater or less than the period of rotation using the original spring
Physics
1 answer:
malfutka [58]3 years ago
6 0

Answer:

The new period of rotation using the new spring would be less than the period of rotation using the original spring

Explanation:

Generally the  period of rotation of the mass is mathematically represented as

       T = 2 \pi \sqrt{\frac{I}{k} }

Here I is the moment of inertia of the mass about the rotation axis and  k is the spring constant

Now looking at the equation we can tell that T is inversely proportional to the square root of the spring constant which means that for a larger spring constant the time period would be lesser

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Need a little help here :(
Goshia [24]

Answer:

The output out be 200

Explanation:

Hope this helps :))

8 0
3 years ago
Read 2 more answers
A 13-kg sled is moving at a speed of 3.0 m/s. At which of the following speeds will the sled have twice as much kinetic energy?
AysviL [449]
K.E. = 1/2 mv²
K.E. is directly proportional to v^2
So, when K.E. increase by 2, K.E. increase by root. 2
v' = 1.41v
original v value was 3 so, final would be:
v' = 1.41*3 = 4.23
After round-off to it's tenth value, it will be:
v' = 4.2

So, option B is your answer!

Hope this helps!

7 0
3 years ago
How much heat is required to convert 0.3 kg of ice at 0°C to water at the same temperature
madreJ [45]

Answer:  

100,800 Jkg


The heat that is used to change the state of a mater is called latent heat.

In this case it is converting ice to water and it is called latent heat of fusion.

It is given by:

Heat  = mc

where m is the mass of ice and l is the specific latent heat of fusion of ice.

l = 0.336 MJ

Heat = 0.3 × 0.336 MJ

        = 0.3 × 0.336 × 10⁶

        = 100,800 Jkg


6 0
3 years ago
Ahmad was moving to the south with v= 10 km/hr ,and Mohammed was moving with half of Ahmad's speed to the North .Write the vecto
Alexxx [7]

Answer:

5 km/hr to the South

Explanation:

VM = VA/2

VM = 10km/2hr =5km/hr

8 0
3 years ago
A 1.0 kilogram ball is thrown into the air with an initial velocity of 30m/s. How much kinetic energy does the ball have? (B) ho
Gala2k [10]

Answer:

450 joules ; 450 joules ; 45.9 m

Explanation:

Given that :

Initial Velocity, u = 30m/s

Mass, m = 1 kg

Kinetic Energy of ball (KE) = 0.5mu²

K. E = 0.5 * 1 * 30^2

K.E = 0.5 * 900

K.E = 450 Joules

B.) Potential Energy (P. E)

P. E = mgh

At the highest point, all kinetic energy has would have become potential energy, hence

K. E = P. E = 450 Joules

C) Height of the ball :

From ; P. E = mgh

Where ; g = acceleration due to gravity = 9.8m/s² ; h = height

450 = 1 * 9.8 * h

450 = 9.8h

h = 450 / 9.8

h = 45.918

h = 45.9 m

7 0
3 years ago
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