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Len [333]
2 years ago
11

What average net force is required to accelerate a 3950 kg bus to a speed of 25m/s in 10.5 s?

Physics
1 answer:
tatuchka [14]2 years ago
6 0

Answer:

Explanation:

ACCELERATION = <u>CHANGE IN VELOCITY </u>

                                          TIME  TAKEN

∴ a = <u>25 - 0 </u>

         10.5

∴ a =  <u> 50  </u>  

           21    

by using f = ma,

we get , f =   3950 ×  <u>50 </u>                                                                                  

                                     21

∴  A FORCE OF 9404.8 N IS NEEDED TO ACCELERATE A BUS OF 3950 KG.

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Answer:

151.9 N

Explanation:

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Acceleration due to gravity is 9.8 m/s^2 (you should memorize this number).

F = ma

F = (15.5)(9.8)

F = 151.9

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No number answer; don't want to pull out a calculator lol

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So for 9, add 10 and 2.5 then do ((1/12.5)+(1/.3))^-1.

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A. That enough light of any frequency would cause electrons to flow.

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A 2,000 kg car starts from rest and coasts down from the top of a 5.00 m long driveway that is sloped at an angel of 20o with th
ehidna [41]

Answer:

The speed at the bottom of the driveway is3.67m/s.

Explanation:

Height,h= 5sin20°= 1.71m

Potential energy PE=mgh= 2000×9.8×1.71

PE= 33516J

KE= PE- Fk ×d

0.5mv^2= 33516 - (4000×5)

0.5×2000v^2= 33516 - 20000

1000v^2= 13516

v^2= 13516/1000

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The base of a hexagonal prism has an apothem measuring 10 inches and an area of 346.41 square inches. the prism is 12 inches tal
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The approximate lateral area of the prism is determined as 831 square inches.

<h3>What is lateral area of the hexagonal prism?</h3>

The lateral area of the hexagonal prism is calculated as follows;

LA = PH

where;

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  • H is height

A = ¹/₂Pa

where;

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  • A is base area = 346.41 in²

346.41 = ¹/₂(10)P

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P = 346.41/5

P = 69.282 inches

LA = PH

LA = 69.282 x 12

LA = 831.38 in²

Learn more about lateral area of prism here: brainly.com/question/296674

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8 0
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