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Len [333]
2 years ago
11

What average net force is required to accelerate a 3950 kg bus to a speed of 25m/s in 10.5 s?

Physics
1 answer:
tatuchka [14]2 years ago
6 0

Answer:

Explanation:

ACCELERATION = <u>CHANGE IN VELOCITY </u>

                                          TIME  TAKEN

∴ a = <u>25 - 0 </u>

         10.5

∴ a =  <u> 50  </u>  

           21    

by using f = ma,

we get , f =   3950 ×  <u>50 </u>                                                                                  

                                     21

∴  A FORCE OF 9404.8 N IS NEEDED TO ACCELERATE A BUS OF 3950 KG.

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n electromagnetic wave in vacuum has an electric field amplitude of 611 V/m. Calculate the amplitude of the corresponding magnet
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Answer:

The  corresponding  magnetic field is  

Explanation:

From the question we are told that

    The electric field amplitude is  E_o   =  611\  V/m

   

Generally the  magnetic  field amplitude is  mathematically represented as

              B_o  =  \frac{E_o }{c }

Where c is the speed of light with a constant value

         c = 3.0 *0^{8} \ m/s

So  

        B_o   =  \frac{611 }{3.0*10^{8}}

         B_o   =  2.0 4 *10^{-6} \  Vm^{-2} s

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         B_o  =  2.0 4 *10^{-6} \ T

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3 years ago
Use the equation PiVi PfVf. Assume that Pi 101 kPa and Vi 10.0 L. If Pf 43.0 kPa, what is Vf
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Apparent brightness depends on which two properties?
Serjik [45]

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On a cold day, snakes usually lie very still and eat little or nothing while birds usually move around and eat a lot of food. Wh
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An arrow is shot at an angle of 35° and a velocity of 50 m/s. How long does it take to return to its original starting height?
Ostrovityanka [42]

Answer:

4.02 s

Explanation:

From the question given above, the following data were obtained:

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