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Len [333]
3 years ago
11

What average net force is required to accelerate a 3950 kg bus to a speed of 25m/s in 10.5 s?

Physics
1 answer:
tatuchka [14]3 years ago
6 0

Answer:

Explanation:

ACCELERATION = <u>CHANGE IN VELOCITY </u>

                                          TIME  TAKEN

∴ a = <u>25 - 0 </u>

         10.5

∴ a =  <u> 50  </u>  

           21    

by using f = ma,

we get , f =   3950 ×  <u>50 </u>                                                                                  

                                     21

∴  A FORCE OF 9404.8 N IS NEEDED TO ACCELERATE A BUS OF 3950 KG.

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If a 0.08 kg cell phone falls off a table at 15 m/s, then what is its kinetic energy right before it hits the ground?
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<h3>Kinetic energy of the phone</h3>

The kinetic energy of the phone right before it hits the ground is calculated as follows;

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