All categories

2 years ago

PLEASE HELP

Mathematics

1 answer:

Reptile [31]2 years ago

5 0

Answer:

so that when we subtract we are subtracting from the corresponding decimal places

Step-by-step explanation:

You might be interested in

PLS PLS PLS HELP!!!! True or false: 6x² - 4y - 3x + 6x² + 8x= 12x² + 5x - 4y

tigry1 [53]

Answer:

True

Step-by-step explanation:

6x² - 4y - 3x + 6x² + 8x = 12x² + 5x - 4y

Regroup terms on left

6x² + 6x² - 3x + 8x - 4y = 12x² + 5x - 4y

Combine like terms

on left

12x² + 5x - 4y = 12x² + 5x - 4y True

7 0

2 years ago

What is 87 24 over 25 as a decimal

erastova [34]

8724/25 = 348.96
When you say "over" that means that it has to be divided that short subtraction sign that separates the numerator and the denominator and also means divide so I believe that if you divide you can find the decimal.

7 0

2 years ago

if the mean of A and B is 20 the mean of B and C is 24 and the mean of A,B and C is 18 .what is the mean of A and C

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

5 0

3 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

2 years ago

How to solve division with exponents

otez555 [7]

In division, exponents with the same base are subtracted.
example:
$\frac{x^4}{x^2} = x^2 \\ \\ \frac{ x^{3} y^{2} }{ x^{6} y} = \frac{y}{ x^{3} } \\ \\ Negative-exponents \\ \\ x^{-2} = \frac{1}{ x^{2} }$

5 0

2 years ago