Answer: 41.46 L
Explanation:
La ecuación que describe relación entre presión, volumen, temperatura y la cantidad (en moles)
de un gas ideal es:
PV = nRT
Donde: P = Presión absoluta
, V= Volumen , n = Moles de gas
, R = Constante universal de los gases ideales, T = Temperatura absoluta,
R = 0.082 L. atm/mol. °K
V = nRT/P
Calculanting n
n = mass/ molecular mass
<h3>n = 4 g / 2g. mol⁻¹</h3><h3>n = 2 mol</h3><h3>T =25⁰ + 273 ⁰K = 298 ⁰K</h3><h3>V = (2 mol ₓ0.082 L. atm / mol.°K x 298 ⁰K) / 1.18 atm = 41.46 L</h3>
Answer: Water and acetone
Explanation: you will find that the water and the soil are polar opposite, while the principal component of the water are Hydrogen and Oxygen, in the acetone you will find a change of carbon, the components from each molecule confer to each one specific physical properties for example the boiling point, and the distillation is a physical separation based on the boiling point.
then you can find the boiling point of the water in 100 °C, and the boiling point of the acetone is 56 °C, this give as a difference of 44 °C,
then while the acetone is boiling the water is liquid state, and this give us the opportunity to the separate the acetone in gas state by condensation after the boiling.
Answer:
2.6166 moles
Explanation:
stp means: T=273k p=101.3kpa
R= 8.31(constant) v=58.6
using the ideal gas law; pv=nRt
101.3 x 58.6 = n x 8.31 x 273
n= (101.3 x 58.6)\(8.31 x 273)
n= 2.6166moles
Answer:
C. 30.0 g NaOH and add water until the final solution has a volume of 3.00 L.
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
from the question ,
M = 0.250M
V = 3.00 L
M = n / V
n = M * v
n = 0.250M * 3.00 L = 0.75 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
n = 0.75 mol NaOH
m = molecular mass of NaOH = 40 g/mol
n = w / m
w = n * m
w = 0.75 mol * 40 g/mol = 30.0 g
Hence , by using 30.0 g of NaOH and dissolving it to make up the volume to 3 L , a solution of 0.250 M can be prepared .
Using ideal gas equation,
PV=nRT
P=199 kpa
V=4.67 L
T=30+273K= 303K
n= number of moles of gas
R=8.321 L·kPa·K-1·mol-1
So using ideal gas equation,
n=PV/RT
=199*4.67/8.321*303\
=0.37 mol
