Bohr changed the model of the atom by proposing that electrons travelled in circular orbits with specific energy levels.
Answer:
–0.13 Pa.m²
Explanation:
From the question given above, the following data were obtained:
Measurement (Pa.mm²) = –1.3×10⁵ Pa.mm²
Measurement (Pa.m²) =?
We can convert from Pa.mm² to Pa.m² by doing the following:
1 Pa.mm² = 1×10¯⁶ Pa.m²
Therefore,
–1.3×10⁵ Pa.mm² = –1.3×10⁵ Pa.mm² × 1×10¯⁶ Pa.m² / 1 Pa.mm²
–1.3×10⁵ Pa.mm² = –0.13 Pa.m²
Thus, –1.3×10⁵ Pa.mm² is equivalent to –0.13 Pa.m².
Same group = same properties, same # of valence electrons
Same period = same # of atomic orbitals
Explanation:
I think
Bonding pairs = 4
Lone pairs around the left chlorine atom = 9
3Fe(s) + 4H2O(l) — 1Fe3O4(s) + 4H2(g)