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kifflom [539]
3 years ago
14

What can be said about the reactants and the products in this reaction?

Chemistry
1 answer:
lord [1]3 years ago
4 0

Answer:

Explanation:

Allstate

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Scientist looking for new substances in plants grind up the plants with methanol. This solvent dissolves many plant compounds. H
liubo4ka [24]

Answer:

See explanation

Explanation:

Crystals can be made from methanol by recrystallizing the plant extract from methanol.

The methanol/water system is heated rapidly using a hot plate and the plant extract dissolves in the heating solution until a clear solution is obtained.

The solution is now cooled rapidly. The interior of the flask used for the re crystallization may even by scratched to assist the quick formation of crystals. Large crystals of plant compounds may be obtained using this method. This process should be carried out in a fume hood because of the toxicity of methanol.

4 0
2 years ago
The atom shown below is?
Volgvan

Answer:

Explanation:

Not likely to form any bonds because in it's last she'll it has 8 electrons and is therefore stable

8 0
2 years ago
What is the molarity of solution that is 5.50 percentage by mass oxalic acid and has a density of 1.024 g/ml
Y_Kistochka [10]

Answer:

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

Explanation:

Mass percentage of oxalic acid = 5.50%

This means that in 100 grams of solution there are 5.50 grams of oxalic acid.

Mass of solution , m = 100

Volume of the solution = V

Density of the solution = d = 1.024 g/mL

V=\frac{m}{d}=\frac{100 g}{1.024 g/mL}=97.66mL

V = 97.66 mL = 0.09766 L

(1 mL = 0.001 L)

Moles of oxalic acid = \frac{5.50 g}{90 g/mol}=0.06111 mol

Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}

The molarity of the solution :

=\frac{0.06111 mol}{0.09766  L}=0.6257M

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

6 0
3 years ago
HELP PLEASE
vodomira [7]

Answer:

4) how charged the object creating the field is and the distance between the two charged objects

3 0
2 years ago
) In another experiment, the student titrated 50.0mL of 0.100MHC2H3O2 with 0.100MNaOH(aq) . Calculate the pH of the solution at
andrew11 [14]

Answer:

Explanation:

moles of acetic acid = 500 x 10⁻³ x .1 M

= 5 X 10⁻³ M

.005 M

Moles of NaOH = .1 M

Moles of sodium acetate formed = .005 M

Moles of NaOH left = .095 M

pOH = 4.8 + log .005 / .095

= 4.8 -1.27875

= 3.52125

pH = 14 - 3.52125

= 10.48

6 0
3 years ago
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