Fluorine-18 is a radioactive isotope of the element fluorine. According to Wikipedia, its half-life is 109.771 minutes, which means the amount present is halved every 109.771 minutes.
You can use the formula for half-life, such that
. You begin with 135 mg fluorine-18. We don't even need to plug in to the formula to see that after 110 min, the amount has halved to equal
67.5 mg.
Noble gases show degrees of reactivity. These elements have generally complete electron shells. Noble Gases Include: Helium, Neon, Argon, Krypton, Xenon, Radon, Ununoctium. Reactive elements that form compounds known as halides.
Answer:
Multivalent Ionic
Explanation:
The type of bond formed between the atoms of two elements can easily be deduced from the magnitude of electronegativity difference between the two bonding atoms.
A summary of electronegativity differences and corresponding types of bonds are shown below as adapted from chemlibretexts, where Δχ is the difference in electronegativity ;
ionic if Δχ ≥ 2.0
polar if 2.0 > Δχ > 0.5
nonpolar if 0.5 > Δχ
To determine the type of bond between Hg and F. Hg has an electronegativity of 2 while F has an electronegativity of 4. the difference in electronegativity (Δχ) is 4 - 2 = 2
This corresponds to a multivalent ionic bond because mercurous ion is the
Hg2^2+ ion and this leads to the formation of Hg2X2 (mercury I fluoride).
Answer:
[OH-] = 1.08x10^-11 M
Explanation:
From the question given,
Concentration of Hydrogen ion, [H+]
= 9.3x10^-4 M
Concentration of Hydroxide ion, [OH-] =..?
The concentration of the hydrogen ion, [H+] and hydroxide ion, [OH-] are related with the following formula:
[H+] x [OH-] = 1x10^-14
Using the above formula, we can easily calculate the concentration of the hydroxide ion, [OH-] as follow:
[H+] x [OH-] = 1x10^-14
[H+] = 9.3x10^-4 M
9.3x10^-4 x [OH-] = 1x10^-14
Divide both side by 9.3x10^-4
[OH-] = 1x10^-14 /9.3x10^-4
[OH-] = 1.08x10^-11 M