Question

What volume in L of a 0.724 M Nal solution contains 0.405 mol of Nal?

Answer 1

Answer:

Explanation:

I added the pictures for anyone struggling with that aspect

Answer 2

Answer:

0.559 L

Explanation:

Step 1: Given data

• Moles of sodium iodide (n): 0.405 mol

• Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)

Step 2: Calculate the volume of solution (V)

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

V = n/M

V = 0.405 mol/(0.724 mol/L) = 0.559 L