Question

During a shrinkage limit test, a 19.3 cm3 saturated clay sample with a mass of 37 g was placed in a porcelain dish and dried in the oven. The oven-dried sample had a mass of 28 g with a final volume of 16 cm3 . Determine the shrinkage limit and the shrinkage ratio.

Answer 1

Answer:

shrinkae limit = 20.35%

shrinkage ratio = 1.45

Explanation:

1. to get the shrinkage limit we would first calculate the moisture content w.

w = (37-28)/28

= 9/28

= 0.3214

then the formula for shrinkage limit is

$[w-\frac{(V-Vd}{wd} ]*100$

w = 0.3214

V = 19.3

Vd = 16

Wd = 28

when we put these values into the formula:

$[0.3214-\frac{(19.3-16)}{28} ]*100$

= 20.35%

2. the shrinkage limit = Wd/V

= 28/19.3

= 1.45