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cestrela7 [59]
3 years ago
9

Which of the following demonstrates a typical project benchmark progression?

Engineering
2 answers:
ivolga24 [154]3 years ago
6 0
Answe C hope that help
Elodia [21]3 years ago
4 0
Anwser c) budget launch,beta site launch,mature site launch.
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Joe is a chemical engineer whose plant discharges heavy metals into the local river. By the test authorized by the city governme
chubhunter [2.5K]

Answer:

B probably

Explanation:

Because the prompt doesn't specify what sort of violation it could be anything maybe when they release the metals during the day and so on.

5 0
3 years ago
You are approaching an intersection on a multiple-lane road, and you want to change lanes;
Ipatiy [6.2K]

Answer:

The correct answer is B

Explanation:

On a multiple lane roadway that has a speed limit of 50 mph (that is 80.5kmh) or greater, a driver is legally required to signal his or her intention to change lanes at least 300 feet   in advance of making the change.

This rule like other traffic rules is design to ensure the safety of other road users by preventing accidents which may stem from reckless driving.

Cheers!

7 0
3 years ago
Read 2 more answers
A group of statisticians at a local college has asked you to create a set of functions that compute the median and mode of a set
iVinArrow [24]

Answer:

Functions to create a median and mode of a set of numbers

Explanation:

def median(list):

   if len(list) == 0:

       return 0

   list.sort()

   midIndex = len(list) / 2

   if len(list) % 2 == 1:

       return list[midIndex]

   else:

       return (list[midIndex] + list[midIndex - 1]) / 2

def mean(list):

   if len(list) == 0:

       return 0

   list.sort()

   total = 0

   for number in list:

       total += number

   return total / len(list)

def mode(list):

   numberDictionary = {}

   for digit in list:

       number = numberDictionary.get(digit, None)

       if number == None:

           numberDictionary[digit] = 1

       else:

           numberDictionary[digit] = number + 1

   maxValue = max(numberDictionary.values())

   modeList = []

   for key in numberDictionary:

       if numberDictionary[key] == maxValue:

           modeList.append(key)

   return modeList

def main():

   print "Mean of [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]: ", mean(range(1, 11))

   print "Mode of [1, 1, 1, 1, 4, 4]:", mode([1, 1, 1, 1, 4, 4])

   print "Median of [1, 2, 3, 4]:", median([1, 2, 3, 4])

main()

3 0
4 years ago
Read 2 more answers
Air initially at 120 psia and 500o F is expanded by an adiabatic turbine to 15 psia and 200o F. Assuming air can be treated as a
Goshia [24]

Answer:

a. Wa = 73.14 Btu/lbm

b. Sgen = 0.05042 Btu/lbm °R

c. Isentropic efficiency is 70.76%

d. Minimum specific work for compressor W = -146.2698 Btu/lbm [It is negative because work is being done on the compressor]

Explanation:

Complete question is as follows;

Air initially at 120 psia and 500oF is expanded by an adiabatic turbine to 15 psia and 200oF. Assuming air can be treated as an ideal gas and has variable specific heat.

a) Determine the specific work output of the actual turbine (Btu/lbm).

b) Determine the amount of specific entropy generation during the irreversible process (Btu/lbm R).

c) Determine the isentropic efficiency of this turbine (%).

d) Suppose the turbine now operates as an ideal compressor (reversible and adiabatic) where the initial pressure is 15 psia, the initial temperature is 200 oF, and the ideal exit state is 120 psia. What is the minimum specific work the compressor will be required to operate (Btu/lbm)?

solution;

Please check attachment for complete solution and step by step explanation

8 0
4 years ago
Air initially at 15 psla and 60 F is compressed to 75 psia and 400 F. The power input to air under steady state condition is 5 h
Triss [41]

Answer:\dot{m}=3.46lbm/min

Explanation:

Initial conditions

P_1=15 psia

T_1=60 F^{\circ}

Final conditions

P_2=75 psia

T_2=400F^{\circ}

Steady flow energy equation

\dot{m}\left [ h_1+\frac{v_1^2}{2}+gz_1\right ]+\dot{Q}=\dot{m}\left [ h_2+[tex]\frac{v_2^2}{2}+gz_2\right ]+\dot{W}

\dot{m}\left [ c_pT_1+\frac{0^2}{2}+g0\right ]+\dot{Q}=\dot{m}\left [ c_pT_2+\frac{0^2}{2}+g0\right ]+\dot{W}

\dot{m}c_p\left [ T_1-T_2\right ]+\left [ -5hp\right ]=\dot{W} -5\times 746\times 3.4121

-4\dot{m}-\dot{m}\times 0.24\times \left [ 400-60\right ]

-81.6\dot{m}-4\dot{m}=-4.949 BTU/sec

\dot{m}=0.057821lbm/sec

\dot{m}=3.46lbm/min

3 0
3 years ago
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