Answer:
Derivative: P’(x) = 200 - 2x
If P’(x) = 0 , x = 100
Therefore P’ is positive and P increases until x = 100
So the maximum units to maximize profits is 100 units
And for 100 units the profit in dollar is:
20000 - 10000 = 10000
10000 dollars
The answer would be (x+3)^2+4
Assume that you only include whole numbers (1,2,3,4,5,6,7,8,9) and not 3.5 and such
so if 1 is odd and less than 5 then it is
1 or 3, since 5 isn't included
then the other number, to be less than 5 when added,
must be
1+x<5
3+x<5
solve each
1+x<5
subtract 1
x<4
set of answers are 1,2,3
3+x<5
subtract 3
x<2
set of answer is 1
so the possible numbers are
1,2,3
that is 3 numbesr out of 9 so
probability=(total desired outcomes)/(total possible outcomes) so
disred outcomes=3
total possible=9
3/9=1/3
the probabiltiy is 1/3
148.57-94 would equal 54.57
Answer:
i think the answer would be B i think if its wrong i am sorry
Step-by-step explanation: