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2 years ago

PLS HELP FOR BRAINLIST!!!!\

Mathematics

2 answers:

gogolik [260]2 years ago

7 0

Answer:

The sum is 41

Step-by-step explanation:

solong [7]2 years ago

4 0

Answer:

1-a-b-c

Step-by-step explanation:

1 + (-a) + (-b) + (-c)

1-a-b-c

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The Library charges a fine each day that a book is late. If Ben recently paid a $3.77 fine for a book that was 13 days late, wha

elixir [45]

total charge = days late * fine

3.77 = 13*fine

divide by 13 on each side

3.77 /13 = fine

.29

The charge is $.29 per day

8 0

3 years ago

Find the values of the variables for which ABCD must be a parallelogram

sleet_krkn [62]

Answer:

y=5 and x=4

Step-by-step explanation:

So,the diagonals of a parallelogram bisect each other..

therefore,we have our two eqn

4x-2=3y-1------------(i)

3y-3=3x

or,y-1=x----------(ii)

Now,simply substitute value of x in eqn (i)

4(y-1)-2=3y-1

or,4y-4-2=3y-1

or,y=5

Again,substitute y=5 in eqn (ii)

5-1=x

therefore,

x=5

Hope it helps you!!!

4 0

3 years ago

Write the number 11 as a fraction with the denominator of 15.

Elanso [62]

Answer:

11/15

there ya go!!

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Plz solve will give brainliest

Levart [38]

Answer:

thank you sa point

Step-by-step explanation:

yun lang sowwey

6 0

2 years ago

A village fete has a children’s running race each year, run in heats of up to ten children. For each heat the first three contes

bekas [8.4K]

Answer: 1) 1/3,654 2) 3/406 3) 72,684,900,288,000 4) 120

<u>Step-by-step explanation:</u>

1) First and Second and Third

$\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}$

2) First and Second

$\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}$

$3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}$

$4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}$

8 0

3 years ago