Question

What volume of concentrated hydrochloric acid (12.0 M HCl) is required to make 2.0 liters of a 3.0 M HCl solution?

Answer 1

Given:

12.0 M HCl

2.0 liters of a 3.0 M HCl

Required:

volume of concentrated hydrochloric acid

Solution:

M1V1 = M2V2

(12.0 M HCl)V1 = (3.0 M HCl)( 2.0 liters)

V1 = (3.0 M HCl)( 2.0 liters)/ (12.0 M HCl)

V1 = 0.5 liters

Answer 2

Answer: The volume of concentrated HCl solution is 0.5 L

Explanation:

To calculate the volume of the concentrated HCl solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ = molarity and volume of the concentrated HCl solution

$M_2\text{ and }V_2$ = Molarity and volume of the diluted HCl solution

We are given:

$M_1=12M\\V_1=?L\\M_2=3M\\V_2=2L$

Putting values in above equation:

$12M\times V_1=3M\times 2L\\\\V_1=0.5L$

Hence, the volume of concentrated HCl solution is 0.5 L