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chubhunter [2.5K]
3 years ago
8

A balloon with a volume of 336.0 mL starts at a temperature of 328K. It is placed in cool water

Chemistry
1 answer:
larisa [96]3 years ago
7 0

Answer:

306.43 K

Explanation:

- Use Charle's law and rearrange formula (V1/T1=V2/T2)

- Hope this helped! Let me know if you would like me to show you step-by-step how to do these types of problems.

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D. What do all of the molecules in the table have in common?
blsea [12.9K]

Answer:

They all have a certain amount of protons electrons and neutrons.

6 0
3 years ago
How many moles are in 1.05 g of gold (Au)?
Wittaler [7]

Answer:

0.005 mol

Explanation:

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

From the question ,

w = given mass of Gold = 1.05 g ,

m = molecular mass of Gold = 197 g/mol

<u>Hence , moles can be calculated as -</u>

n = w / m = 1.05 g / 197 g/mol = 0.005 mol

7 0
2 years ago
How many valence electrons does magnesium (Mg) have?Question options:A) 6B) 2C) 12D) 0
wel

INFORMATION:

We must find the number of valence electrons for magnesium

STEP BY STEP EXPLANATION:

In order to know the number of valence electrons for Mg, we need to locate the element in the periodic table

Since Mg is in the second group of the periodic table, it has two valence electrons.

ANSWER:

B) 2

4 0
1 year ago
A hypothetical element x has 3 naturally occurring isotopes: 41.20% of 21x, with an atomic weight of 21.016 amu, 50.12% of 22x,
iogann1982 [59]
The average atomic weight is calculated by adding up the products of the percentage abundance and atomic weight. In this item, we have the equation,

     A = (0.412)(21.016 amu) + (0.5012)(21.942 amu) + (0.0868)(23.974 amu)

Simplifying the operation will give us the answer of 21.74 amu.

<em>Answer: 21.74 amu</em>
4 0
3 years ago
Barbiturates are synthetic drugs used as sedatives and hypnotics. Barbital ( = 184.2 g/mol) is one of the simplest of these drug
DanielleElmas [232]

Answer:

118.75°C is the boiling point of a solution.

Explanation:

Mass of the solute that is barbiturates = 42.5 g

Molar mass of a solute = 184.2 g/mol

Moles of solute = \frac{42.5 g}{184.2 g/mol}=0.2307 mol

Mass of the solvent that acetic acid = 825 g = 0.825 kg

molality=\frac{\text{Moles of solute}}{\text{Mass of solvent}}

Molality of the solution (m):

m=\frac{0.2307 mol}{0.825 kg}=0.2796 m

Elevation in boiling point is given as:

\Delta T_b=i\times K_b\times m

i = 1 (organic compound)

=1\times 3.07^oC/m\times 0.2796 m=0.8585^oC

\Delta T_b=T_b-T

T_b = Boiling temperature of solution.

T = boiling temperature of solvent that is acetic acid=117.9°C

0.8585^oC=T_b-117.9^oC

T_b=118.75 ^oC

118.75°C is the boiling point of a solution.

6 0
3 years ago
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