Answer:
a. A = 0.1656 m
b. % E = 1.219
Explanation:
Given
mB = 4.0 kg , mb = 50.0 g = 0.05 kg , u₁ = 150 m/s , k = 500 N / m
a.
To find the amplitude of the resulting SHM using conserver energy
ΔKe + ΔUg + ΔUs = 0
¹/₂ * m * v² - ¹/₂ * k * A² = 0
A = √ mB * vₓ² / k
vₓ = mb * u₁ / mb + mB
vₓ = 0.05 kg * 150 m / s / [0.050 + 4.0 ] kg = 1.8518
A = √ 4.0 kg * (1.852 m/s)² / (500 N / m)
A = 0.1656 m
b.
The percentage of kinetic energy
%E = Es / Ek
Es = ¹/₂ * k * A² = 500 N / m * 0.1656²m = 13.72 N*0.5
Ek = ¹/₂ * mb * v² = 0.05 kg * 150² m/s = 1125 N
% E = 13.72 / 1125 = 0.01219 *100
% E = 1.219
Answer: V = 3.4 L
Explanation: Use Boyle's Law to find the new volume. P1V1 = P2V2, derive for V2, then the formula will be V2= P1V1 / P2
V2 = 2.5 atm ( 4.5 L ) / 3.3 atm
= 3.4 L
Given :
Liquid is poured into a burrete so that it reads 14cm³.
50 drops were run each of volume 0.1cm³ .
To Find :
The volume of liquid in burrete after 50 drops.
Solution :
Volume of each drop, v = 0.1 cm³.
Initial volume in burrete, V = 14 cm³.
Now, volume left after droping 50 drops are :
Therefore, the volume left in burrete is 9 cm³ .
it will move the object if you apply force, because of that it will stay the same with newton's law.
Answer:
<em>-2 units of charge</em>
Explanation:
charge on A = Qa = -6 units
charge on B = Qb = 2 units
if the spheres are brought in contact with each other, the resultant charge will be evenly distributed on the spheres when they are finally separated.
charge on each sphere will be = 
charge on each sphere = 
= 
= <em>-2 units of charge</em>
