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Pie
3 years ago
5

If the 50 kg boy were in a spacecraft 5.0r from the center of the earth, what would his weight be?

Physics
1 answer:
Lady_Fox [76]3 years ago
7 0
·The acceleration of gravity is proportional to

                       1 / (the square of the distance from the center) .

When we're on the surface, we're 1 radius from the center of the Earth,
and the acceleration of gravity is  9.8 m/s² .

The boy's weight = (mass) · (gravity) = (50kg) · (9.8 m/s²)

                                                             =      490 newtons .

At the distance of 5 radii from the center (4 radii altitude from the surface),
the acceleration of gravity is

                 (9.8 m/s²) · (1/5)²  =  0.39 m/s² .

The boy's weight is    (mass) · (gravity)  =  (50kg) · (0.39 m/s²)

                                                                  =     19.6 newtons .

Just as we expected, his weight at that distance is

         (19.6 / 490) = 0.04  =  1/25  =  1/5²  of his weight on the surface.
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According to the information in the fragment, it can be inferred that it is an example of how scientific development has consequences on pre-established theories and new areas are created in science (option C)

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<h2>\large{\underbrace{\underline{\fcolorbox{White}{pink}{\bf{ANSWER♥︎}}}}}</h2><h3>kinetic energy is given as</h3>

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I=5AandB=0.20TI=5AandB=0.20T

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