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Otrada [13]
3 years ago
10

A(n) 93 kg clock initially at rest on a horizontal floor requires a(n) 617 N horizontal force to set it in motion. After the clo

ck is in motion, a horizontal force of 528 N keeps it moving with a constant velocity. The acceleration of gravity is 9.81 m/s 2 . a) Find µs between the clock and the floor
Physics
1 answer:
Viefleur [7K]3 years ago
5 0

Answer:

\mu_s = 0.676

Explanation:

As we know that the force required to move the clock from rest position must be equal to the maximum limiting friction

So we will have

F = F_f

now we know that

F_f = \mu_s Mg

here we will have

F = 617 N

m = 93 kg

now from above formula we will have

617 = \mu_s (93)(9.81)

\mu_s = 0.676

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A soccerball is kicked straight out from a hill at 15 m/s and lands 42m away. how tall is the hill
ozzi

Answer:

The height of the hill is, h = 38.42 m

Explanation:

Given,

The horizontal velocity of the soccer ball, Vx = 15 m/s

The range of the soccer ball, s = 42 m

The projectile projected from a height is given by the formula

                             S = Vx [Vy + √(Vy² + 2gh)] / g

Therefore,

                            h = S²g/2Vx²                     (Since Vy = 0)

Substituting the values

                             h = 42² x 9.8/ (2 x 15²)

                                = 38.42 m

Hence, the height of the hill is, h = 38.42 m

4 0
3 years ago
a tire has a tread pattern with a crevice every 4.00 cm. each crevice makes a single vibration as the tire moves. what is the fr
koban [17]

the frequency (in hz) of these vibrations if the car moves at 24.2 m/s is 605 HZ .

Calculation :

frequency = \frac{number of contacts}{second}

frequency = \frac{24.2 m/s}{1}*100cm*\frac{1}{4cm}

= 605 HZ

Frequency describes the number of waves passing through a particular location in a particular time. So if the wave takes 1/2 second to travel, the frequency is 2 per second. If it takes 1/100th of an hour, the frequency is 100 per hour.

Frequency is the number of occurrences of a repeating event per unit time. ... sometimes called time-frequency for clarity,

Learn more about frequency here : brainly.com/question/254161

#SPJ4

5 0
1 year ago
PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!
Svetach [21]
There’s no image ???
4 0
3 years ago
1. What are three questions you should ask before joining a club?
lara [203]

Answer:

what time does it start.

what do I need to join.

what are your expectations.

7 0
3 years ago
A 30.0 g mass of iron at 24.5°C is heated to 45.0°C. The theoretical specific
diamong [38]

Answer:

276.135 J

Explanation:

Given that:

mass of Fe = 30.0 g

initial temperature = 24.5°C

final temperature = 45.0°C

specific heat of Fe = 0.449 J/g°C

We can determine the thermal energy added by using the formula;

Q = mcΔT

Q = 30.0g × 0.449 J/g°C × (45.0 - 24.5)°C

Q = 276.135 J

8 0
3 years ago
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