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Otrada [13]
3 years ago
10

A(n) 93 kg clock initially at rest on a horizontal floor requires a(n) 617 N horizontal force to set it in motion. After the clo

ck is in motion, a horizontal force of 528 N keeps it moving with a constant velocity. The acceleration of gravity is 9.81 m/s 2 . a) Find µs between the clock and the floor
Physics
1 answer:
Viefleur [7K]3 years ago
5 0

Answer:

\mu_s = 0.676

Explanation:

As we know that the force required to move the clock from rest position must be equal to the maximum limiting friction

So we will have

F = F_f

now we know that

F_f = \mu_s Mg

here we will have

F = 617 N

m = 93 kg

now from above formula we will have

617 = \mu_s (93)(9.81)

\mu_s = 0.676

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