Ok, this is a ratio problem; the ratio of the length to width is constant (and therefore equal): 4 /6 = 15 / x Now, with a ratio, we may do any allowable algebra operation: cross-multiply, invert both sides, multiply or divide both sides by the same amount, etc. Let's cross-multiply: 4x = (15)(6) x = 90/4<span> x = 22.5 in. </span>
Answer:
(2, 7) is the correct ordered pair.
Step-by-step explanation:
5x + 3y = 31
2x + 3y = 25 Subtract to eliminate the y variable:
3x = 6
x = 6/3
x = 2.
Substitute x = 2 in the first equation:
5*2 + 3y = 31
3y = 31-10 = 21
y = 21/3
y = 7.
Check the result by substituting for x and y in the second equation:
2(2) + 3(7) = 25
4 + 21 = 25
25 = 25.
Answer:
id say A
because its an opened circle, and when its opened its usually not with the little dash and there's no negative number (that i know of)
<u>Hello:</u>
<u />
<u>Okay, this problem should be taken in a series of steps</u>:
<u>What is the slope's formula?</u>

- (x₁,y₁) -- first point
- (x₂,y₂) -- second point
<u>Okay, now let's use this knowledge</u>
10. (5,-19) and (-5,21)

11. (12,1) and (12, -1)

12. (8,7) and (4,7)

<u>Answer:</u>
- Question 10: -4
- Question 11: undefined
- Question 12: 0
Hopefully that helps!
Answer:
- B) One solution
- The solution is (2, -2)
- The graph is below.
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Explanation:
I used GeoGebra to graph the two lines. Desmos is another free tool you can use. There are other graphing calculators out there to choose from as well.
Once you have the two lines graphed, notice that they cross at (2, -2) which is where the solution is located. This point is on both lines, so it satisfies both equations simultaneously. There's only one such intersection point, so there's only one solution.
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To graph these equations by hand, plug in various x values to find corresponding y values. For instance, if you plugged in x = 0 into the first equation, then,
y = (-3/2)x+1
y = (-3/2)*0+1
y = 1
The point (0,1) is on the first line. The point (2,-2) is also on this line. Draw a straight line through the two points to finish that equation. The other equation is handled in a similar fashion.