1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zarrin [17]
2 years ago
13

James cut out four parallelograms, the dimensions of which are shown below. Parallelogram 1 length: 12 in. width: 15 in. diagona

l: 20 in. Parallelogram 2 length: 16 in. width: 30 in. diagonal: 34 in. Parallelogram 3 length: 20 in. width: 21 in. diagonal: 29 in. Parallelogram 4 length: 18 in. width: 20 in. diagonal: 26 in. James put the parallelograms together so one vertex from each paper exists on a point, as shown in the circle. 4 parallelograms are put together so that one vertex from each paper exists on a point. Which statement explains whether or not the parallelgrams can be put together so each occupies one-quarter of the area of the circle without overlapping any other pieces? Check all that apply. The quadrilaterals can be placed such that each occupies one-quarter of the circle. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 2 do not form right angles. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 3 do not form right angles. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.

Mathematics
1 answer:
Alenkinab [10]2 years ago
3 0

Answer: by the looks of this its 2

You might be interested in
Simplify <br>28y=12x+84<br>I don't know this
irina1246 [14]
Divide everything by 4 getting:
7y=3x+21
then get all of the variables on one side by subtracting 3x:
7y-3x=21
7 0
3 years ago
Help me, please !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
erica [24]

Answer:

The first one is the answer

3 0
3 years ago
What is a number less than 130 that rounds to 130 when rounding to the nearest ten
lilavasa [31]

Answer:

129.99

Step-by-step explanation:

129.99 rounds to 130 because the 9 in the hundredths place causes the 9 in the tenths place to round up, making the number 130.0.

7 0
2 years ago
Read 2 more answers
Based on the theoretical probability, how many times would you expect to pick a yellow skittle if you pick 150 times?
Fudgin [204]

Answer:

why are you digging through skittles 150 times?

8 0
3 years ago
Read 2 more answers
Can someone help me at this
anygoal [31]

Answer:

a - 2

Step-by-step explanation:

Perimeter = side 1 + side 2 + side 3

So

6a + 3 = 2(a + 3) + (3a - 1) + side 3

side 3 = (6a + 3) - (2a + 6) - (3a - 1)

side 3 = 6a - 2a - 3a + 3 - 6 + 1 = a - 2

8 0
2 years ago
Read 2 more answers
Other questions:
  • ABCD ~ WXYZ. AD = 6, DC = 3, and WZ = 59. Find YZ.
    7·1 answer
  • Use the whole number product and place value reasoning to place the decimal point in the second product. Explain how you know.
    12·2 answers
  • Create a system of equations that includes one linear equation and one quadratic equation.
    14·1 answer
  • What is the area of the regular hexagon with a side length of 3 cm and an apothem of 2.6 cm? A. 15.6 cm2 B. 23.4 cm,2 C. 46.8 cm
    12·2 answers
  • Find the area of the regular hexagon.<br><br> Round to the nearest hundredth.
    11·1 answer
  • Write 3 to the -4 power using a positive exponent.
    11·1 answer
  • Find the surface area of the rectangular prism
    13·1 answer
  • The water level of a lake fell by 1 1/2 in. during a 3 3/4 ​-week-long dry spell. Simplify the complex fraction below to find th
    10·2 answers
  • Use the graph to determine the domain and range of the function
    5·1 answer
  • Determine the range of the following graph:
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!