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zzz [600]
3 years ago
5

When taking a measurement with a pH meter, keep the instrument in the ______________ until it is needed. Rinse the pH meter with

______________ and gently pat dry. Place the meter in the sample solution, and record the measurement when the pH __________
Chemistry
1 answer:
nydimaria [60]3 years ago
8 0

Answer:

Storage solution; deionized water; stabilizes.

Explanation:

The pH scale measures the concentration of hydrogen ions in acidic and alkaline solutions.

In chemistry, it literally means power of hydrogen ions and it is a measure of the molar concentration of hydrogen ions in a particular solution, thus specifying the acidity, neutrality or basicity of chemical solutions.

Mathematically, the pH of a solution is given by;

pH = -log_{10}(H^{+})

Hence, a solution with a pH of 7 is neutral. Also, a solution with a pH below 7 is acidic but basic (alkaline) if it's pH is above 7.

A pH meter can be defined as a scientific instrument or device designed and developed for the measurement of the hydrogen-ion concentration in water-based solutions, in order to determine their level of acidity or alkanility.

When using a pH meter to take a measurement, you should keep it in a storage solution until it is needed. Also, a deionized water should be used to rinse the pH meter and gently pat dry.

Furthermore, the pH meter should be placed in a given sample solution and a reading of the measurement taken when the pH of the solution stabilizes.

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I just wanna know what does that even mean
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Initial Concentration mol/L[A] Initial Concentration mol/L[B] Initial Rate mol/Ls 0.20 0.10 20 0.20 0.20 40 0.40 0.20 160 Given
zimovet [89]
The generalized rate expression may be written as:
r = k[A]ᵃ[B]ᵇ

We may determine the order with respect to B by observing the change in rate when the concentration of B is changed. This can be done by comparing the first two runs of the experiment, where the concentration of A is constant but the concentration of B is doubled. Upon doubling the concentration of B, we see that the rate also doubles. Therefore, the order with respect to concentration of B is 1.
The same can be done to determine the concentration with respect to A. The rate increases 4 times between the second and third trial in which the concentration of B is constant, but that of A is doubled. We find that the order with respect to is 2. The rate expression is:

r = k[A]²[B]
4 0
3 years ago
Read 2 more answers
List the colors of light in the visible spectrum in order<br> of increasing frequency.
masya89 [10]

Answer:

Violet 400 - 420 nm

Indigo 420 - 440 nm

Blue 440 - 490 nm

Green 490 - 570 nm

Yellow 570 - 585 nm

Orange 585 - 620 nm

Red 620 - 780 nm

Explanation:

5 0
3 years ago
What are the spectator ions in the reaction between mg(oh)2 (aq) and hcl (aq)?
vivado [14]

The spectator ions in the reaction between aqueous Mg(OH)_2 and aqueous HCl would be   Mg^{2+ and Cl^- ions.

<h3>What are spectator ions?</h3>

Spectator ions are anions or cations that exist both as reactants and as products in a reaction. Their forms remain unchanged both in the reactants and in the products.

Aqueous Mg(OH)_2 and aqueous HCl  react according to the following equation:

Mg (OH)_2 (aq) + 2HCl (aq) --- > MgCl_2 (aq) +2 H_2O (l)

Before the reaction, Mg^{2+ and Cl^- existed in the reactants as Mg(OH)_2 and HCl respectively. After the reaction,  Mg^{2+ and Cl^- exist as MgCl_2 in the product.

Thus, the spectator ions in this case are  Mg^{2+ and Cl^- ions because their forms did not change after the reaction.

More on spectator ions can be found here: brainly.com/question/28913274

#SPJ1

6 0
1 year ago
A total of 2.00 mol of a compound is allowed to react with water in a foam coffee cup and the reaction produces 126 gg of soluti
lina2011 [118]

Answer : The enthalpy of this reaction is, 0.975 kJ/mol

Explanation :

First we have to calculate the heat produced.

q=m\times c\times (T_2-T_1)

where,

q = heat produced = ?

m = mass of solution = 126 g

c = specific heat capacity of water = 4.18J/g^oC

T_1 = initial temperature = 21.00^oC

T_2 = final temperature = 24.70^oC

Now put all the given values in the above formula, we get:

q=126g\times 4.18J/g^oC\times (24.70-21.00)^oC

q=1948.716J=1.95kJ

Now we have to calculate the enthalpy of this reaction.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat released = 1.95 kJ

n = moles of compound = 2.00 mol

Now put all the given values in the above formula, we get:

\Delta H=\frac{1.95kJ}{2.00mole}

\Delta H=0.975kJ/mol

Thus, the enthalpy of this reaction is, 0.975 kJ/mol

4 0
3 years ago
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