<span>You must multiply the bond enthalpy by each broken or formed bond.
The C - H bond = 414k Joules/ mol, but that is only applicable per bond.
The C3H8 molecule has 8*C-H bonds that have to break. You have to account all the bonds that break and form to get the DH for the reaction.
Because of the Lewis structure of Propane C3h8 you only use 8 in </span><span>c3h8 has 3-C and 8-C.</span>
The radii of most atoms are actually measured in the Ǻ, or Angstrom. We can do it in nanometers too, however.
<span>First, we take the radius of the smallest atom, He (Helium). Atomic radius = .031 nm. The largest atom, stable atom is Fr (Francium), with atomic radius = .27 nm. </span>
<span>Therefore, the typical atomic radius is between .031 and .27 nm.</span>
Answer:C3H8 +5O2-- >3CO2+4H2O, 330L of air,Hof C3H8= 2323.7 KJ/mol,dT=75.30
Explanation:
First We need to find a balanced equation to depict the combustion of the propane:
C3H8 +5O2-- >3CO2+4H2O
b)
330L of air
25 g C3H8 are equal to 44g and 5 mol of O2 will react with a mol of C3H8, each mol of O2 weigh 32g and for each L of air contains 0.275g of O2
c) 
the enthalpy of formation of propane will be the negative of the sum of the enthalpy of formation multiplied by the mols of the H2O and CO2
Hof C3H8= 2323.7 KJ/mol
d) We know that each 44g of C3H8(1mol) transfer 2219.2 KJ then:
= 1260.9KJ
We use the equation of heat transfered
Q=mCpdT
1260.9KJ= 4KJ *4.186KJ/Kg*°C *dT
We clear the equation
Q/mCp=dT
dT=75.30
Answer: can u explain ur question please?
Explanation:
Answer:
1 tell your family difrent ways to safe water
2 dont leave the water running when you brush your teeth
3 dont dump cups of water out for no reason
Explanation:
