Answer:
electrons
Explanation:
The magnitude of the electric field outside an electrically charged sphere is given by the equation
where
k is the Coulomb's constant
Q is the charge stored on the sphere
r is the distance (from the centre of the sphere) at which the field is calculated
In this problem, the cloud is assumed to be a charged sphere, so we have:
is the maximum electric field strength tolerated by the air before breakdown occurs
is the radius of the sphere
Re-arranging the equation for Q, we find the maximum charge that can be stored on the cloud:
Assuming that the cloud is negatively charged, then
And since the charge of one electron is
The number of excess electrons on the cloud is
Answer:
Some examples of levers include more than one class, such as a nut cracker, a stapler, nail clippers, ice tongs and tweezers. Other levers, called single class levers include the claw end of a hammer.
Explanation:
Answer:
Because on different surfaces there's more/less friction. Smooth surfaces will allow the duster to accelerate while rough surfaces will decrease the acceleration.
Explanation:
<em>S</em><em>p</em><em>e</em><em>e</em><em>d</em><em> </em><em>is </em><em> </em><em>defi</em><em>ned</em><em> </em><em>as </em><em>distance</em><em> </em><em>per</em><em> </em><em>tim</em><em>e</em><em> (</em><em>mil</em><em>es</em><em> </em><em>per</em><em> </em><em>hou</em><em>r</em><em> </em><em>or</em><em> </em><em>meter</em><em> </em><em>per</em><em> </em><em>se</em><em>cond</em><em>)</em>
Answer:
<em>The Strength of the electric field produced = 2 × 10⁷ N/C</em>
Explanation:
<em>Electric Field:</em> This is defined as the region where an electric force is experienced.
<em>Electric Field Strength: </em><em>The intensity of an electric field at any point is defined as the force per unit charge which it exert at that point. It direction is that of the force exerted on a positive charge.</em>
<em>It is represented mathematically as,</em>
<em>E = F/Q ................................. Equation 1</em>
<em>Where E = Electric field strength, F = electric force, Q = test charge.</em>
<em>Given: F = 3.2 × 10⁻⁴ N, Q = 1.6 × 10⁻¹¹ C</em>
<em>Substituting these values into equation 1</em>
<em>E= 3.2 × 10⁻⁴/1.6 × 10⁻¹¹ </em>
<em>E= 2 × 10⁷ N/C</em>
<em>Thus the Strength of the electric field produced = 2 × 10⁷ N/C</em>
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