Neglecting losses in a transformer, it's input and output <em>power </em>are equal.<em> (C)</em>
Answer:
2.5 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity.
The S.I unit of acceleration is m/s²
For circular motion, the expression for acceleration is given as,
a = ω²r ................ Equation 1
Where a = acceleration of the particle, ω = angular speed of the particle, r = radius of the circular path.
Given: ω = 5 rev/s = 31.42 rad/s, r = 0.10 m.
Substitute into equation 1
a = 5²(0.10)
a = 25(0.10)
a = 2.5 m/s²
Hence the acceleration of the particle = 2.5 m/s²
Hence, none of the option is correct
Answer:
5 N
Explanation:
From the question,
The magnitude of the force that would be required to just loosen the nut when the force is applied perpendicularly at the end of the handle is
Fy = Fsinθ................. Equation 1
Where Fy = force acting perpendicular at the end of the handle, F = Force applied to the handle, θ = angle of inclination of the force to the end of the handle.
Given: F = 10 N, θ = 30°
Substitute these values into equation 1
Fy = 10(sn30°)
Fy = 10(0.5)
Fy = 5 N.
Answer:
A. 3.3 m
Explanation:
Here, we have to use conservation of energy principle.
When the ball is at maximum height, the instantaneous velocity at that point is 0 m/s. So, the kinetic energy of the ball is also 0 at the maximum height. Thus, at maximum height, the energy possessed by the ball is gravitational potential energy only.
Now, when the ball reaches the ground, all the gravitational potential energy changes into kinetic energy because of the conservation of energy.
Therefore, the energy transformation can be given as:
Decrease in potential energy = Increase in Kinetic energy
Decrease in potential energy is given as:
Increase in kinetic energy is given as:
Therefore,
Now, plug in 8 for , 9.8 for and solve for height . This gives,
Therefore, the maximum height reached by the ball is 3.3 m.