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vekshin1
3 years ago
9

Opposite poles of different magnets will attract each other and like poles will repel each other. This is an example of which of

the following?lawhypothesistheory
Physics
2 answers:
sasho [114]3 years ago
6 0
The Law of Attraction or Theory of Magnetism
Stolb23 [73]3 years ago
4 0

Answer:

Explanation: Opposite poles of different magnets attract each other whereas same poles repel each each other this is an example of theory of magnetism and law of attraction that opposites attract. In case of magnets north- north and south- south poles repel each other while north-south and south - north attracts each other. Since earth is a big magnet and its magnetic north and south pole follows the same rule of attraction.

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Usimov [2.4K]

Answer:

» Projectile motion is a curved graph.

☑ This is because projectile motion consists of both vertical and horizontal motion, with one starting angle. Hence as the body starts motion, it is acted upon by gravity.

At point v = 0, the motion is free from gravity hence approaching horizontal motion.

Examples;

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2 years ago
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An aircraft is in level flight at 225 km/hr through air at standard conditions. The lift coefficient at this speed is 0.45 and t
mojhsa [17]

Answer:

- the effective lift area for the aircraft is 8.30 m²

- the required engine thrust is 1275 N

- required power is 79.7 kW

Explanation:

Given the data in the question;

Speed V = 225 km/hr = 62.5 m/s

The lift coefficient CL = 0.45

drag coefficient CD = 0.065

mass = 900 kg

g = 9.81 m/s²

a)  the effective lift area for the aircraft

we know that for a steady level flight, weight = lift and thrust = drag

Using the equation for the lift force

F_L = C_L\frac{1}{2}ρV²A = W

we substitute

0.45 × \frac{1}{2} × 1.21 × ( 62.5 )² × A = ( 900 × 9.81 )

1081.05 × A = 8829

A = 8829 / 1081.05

A = 8.30 m²

Therefore, the effective lift area for the aircraft is 8.30 m²

b) the required engine thrust and power to maintain level flight.

we use the expression for drag force

F_D = T = C_D\frac{1}{2}ρV²A

we substitute

= 0.065 × \frac{1}{2} × 1.21 × ( 62.5 )² × 8.30

T = 1275 N

Since drag and thrust force are the same,

Therefore, the required engine thrust is 1275 N

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P = TV

p = 1275 × 62.5

p = 79687.5 W

p = ( 79687.5 / 1000 )kW

p = 79.7 kW

Therefore, required power is 79.7 kW

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<h3>What is a Moon maria?</h3>

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