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3 years ago

What is the primary tool material used for CNC turning?

Engineering

1 answer:

Marizza181 [45]3 years ago

8 0

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A piston moves a 25kg hammerhead vertically down 1m from rest to a

UkoKoshka [18]

Answer:

Total change in energy = 31 KJ.

Explanation:

Mass m=25 kg

Height h = 1 m

Initial velocity = 0

Final velocity = 50 m/s

Energy at initial condition

$E_1=mgh+\dfrac{1}{2}mv^2$

$E_1=25\times 10\times 1+0$

$E_1=250\ J$

Energy at final condition

$E_2=0+\dfrac{1}{2}\times 25\times 50^2$

$E_2=31250\ J$

So the change in energy = 31250 -250 J

The total change in energy = 31000 J

5 0

4 years ago

Read 2 more answers

What is the advantage of having the engine in the front of the car?

Ugo [173]

Answer:

<h2>No advantages bro!!</h2>

Explanation:

hehehehe DONTTTT report my answer

8 0

3 years ago

Read 2 more answers

A road has a crest curve, where the PVI station is a 71 35. The road transitions from a 2.1% grade to a -3.4% grade. The highest

sveticcg [70]

Answer:

Stat PVC = Stat(82+98.5)

Stat PVT = Stat(59+71.5)

Explanation

PVI = 71 + 35

Let G1 = Grade 1; G2 = Grade 2

G1 = +2.1% ; G2 = -3.4%

Highest point of curve at station = 74 + 10

General equation of a curve:

$y = ax^{2} +bx+c\\dy/dx=2ax+b\\$

At highest point of the curve $dy/dx=o$

$2ax+b=0\\x=-b/2a\\x=G1L/(G2-G1)\\x=L/2 +(stat 74+10)-(stat 71+35)\\x=L/2 + 275$

$-G1L/(G2-G1) = (L/2 + 275)/100\\L = -2327 ft\\Station PVC = Stat(71+35)+(-2327/2)\\\\Stat PVC = 7135-1163.5\\Stat PVC = Stat(82+98.5)\\$

Station PVT

$Station PVT = Stat PVI + (L/2)\\Station PVT = Stat(71+35)+(-2327/2)\\Station PVT = 7135-1163.5\\Stat PVT = Stat(59+71.5)$

3 0

3 years ago

A 60-cm-high, 40-cm-diameter cylindrical water tank is being transported on a level road. The highest acceleration anticipated i

dlinn [17]

Answer:

$h_{max} = 51.8 cm$

Explanation:

given data:

height of tank = 60cm

diameter of tank =40cm

accelration = 4 m/s2

suppose x- axis - direction of motion

z -axis - vertical direction

$\theta$ = water surface angle with horizontal surface

$a_x =$ accelration in x direction

$a_z =$ accelration in z direction

slope in xz plane is

$tan\theta = \frac{a_x}{g +a_z}$

$tan\theta = \frac{4}{9.81+0}$

$tan\theta =0.4077$

the maximum height of water surface at mid of inclination is

$\Delta h = \frac{d}{2} tan\theta$

$=\frac{0.4}{2}0.4077$

$\Delta h 0.082 cm$

the maximu height of wwater to avoid spilling is

$h_{max} = h_{tank} -\Delta h$

= 60 - 8.2

$h_{max} = 51.8 cm$

the height requird if no spill water is $h_{max} = 51.8 cm$

3 0

4 years ago

Technician A says that the first step in diagnosing engine condition is to perform a thorough visual inspection. Technician B sa

mojhsa [17]

Answer:

Technician A

Explanation: Technician A is correct. Technician B is wrong, as an oil leak can trickle down onto other engine components, away from where the leak actually is.

5 0

3 years ago