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Black_prince [1.1K]
3 years ago
6

The first electricity producing wind turbine was invented in what year?*

Engineering
1 answer:
irina [24]3 years ago
3 0
The first wind turbine was invented in 1888
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Engine oil flows through a 25‐mm‐diameter tube at a rate of 0.5 kg/s. The oil enters the tube at a temperature of 25°C, while th
Elodia [21]

Answer:

a) the log mean temperature difference (Approx. 64.5 deg C)

b) the rate of heat addition into the oil.

The above have been solved for in the below workings

Explanation:

3 0
4 years ago
What are the 3 dimensions that used in isometric sketches?
noname [10]

Answer:

The three dimensions shown in an isometric drawing are the height, H, the length, L, and the depth, D

Explanation:

An isometric drawing of an object in presents a pictorial projection of the object in which the three dimension, views of the object's height, length, and depth, are combined in one view such that the dimensions of the isometric projection drawing are accurate and can be measured (by proportion of scale) to draw the different views of the object or by scaling, for actual construction of the object.

5 0
3 years ago
A heat pump is used to warm a building in the winter. This system implements an ideal vapor-compression cycle with R-134a as the
Marrrta [24]

Answer:

See attachment for detailed answer.

Explanation:

Download pdf
5 0
3 years ago
A geothermal pump is used to pump brine whose density is 1050 kg/m3 at a rate of 0.3 m3/s from a depth of 200 m. For a pump effi
nasty-shy [4]

Answer:

Input power of the geothermal power will be 686000 J

Explanation:

We have given density of brine \rho =1050kg/m^3

Rate at which brine is pumped V=0.3m^3/sec

So mass of the pumped per second

Mass = volume × density = 1050\times 0.3=315 kg/sec

Acceleration due to gravity g=9.8m/sec^2

Depth h = 200 m

So work done W=mgh=315\times 9.8\times 200=617400J

Efficiency is given \eta =0.9

We have to fond the input power

So input power =\frac{617400}{0.9}=686000J

So input power of the geothermal power will be 686000 J

5 0
3 years ago
The driveshaft of an automobile is being designed to transmit 134 hp at 2900 rpm. Determine the minimum diameter d required for
Misha Larkins [42]

Answer:

The minimum diameter is 1.344 in

Explanation:

The angular speed of the driveshaft is equal to:

w=\frac{2\pi N}{60}

Where

N = rotational speed of the driveshaft = 2900 rpm

w=\frac{2\pi *2900}{60} =303.69rad/s

The torque in the driveshaft is equal to:

\tau=\frac{P}{w}

Where

P = power transmitted by the driveshaft = 134 hp = 73700 lb*ft/s

\tau=\frac{73700}{303.69}  =242.68lb*ft

The minimum diameter is equal to:

d_{min} =(\frac{16T}{\pi *\tau } )^{1/3}

Where

T = shear stress = 6100 psi

τ = 242.68 lb*ft = 2912.16 lb*in

d_{min} =(\frac{16*2912.16}{\pi *6100} )^{1/3} =1.344in

4 0
3 years ago
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