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Anettt [7]
3 years ago
14

Net force is also a vector quantity which has both magnitude and direction. Using complete sentences, describe the net force act

ing upon the object during the course of the elliptical orbit. Comment on both the magnitude and the direction.
Physics
1 answer:
loris [4]3 years ago
7 0

Answer:

In this movement, both the magnitude and the direction of the force change

Explanation:

A body that moves in an elliptical path must be subjected to a force that is pointed towards one of the foci, therefore the force is central.

The magnitude of this force must be greater when the two bodies are closer and its directional changes, but it always points to the focus where the body that originates the force is.

In this movement, both the magnitude and the direction of the force change

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explain how the composition of a star that will form a billon years in the future will differ the composition of our sun.
Grace [21]

Answer:

Explanation:

Basically the star slowly burns its hydrogen into Helium. Depending on the mass, the star will have a turbulent core where the Helium will be fully mixed or a radiative core where the helium will settle at the centre (remember it's heavier than Hydrogen). The second case is what happens in the Sun.

3 0
3 years ago
The triceps muscle in the back of the upper arm is primarily used to extend the forearm. Suppose this muscle in a professional b
bagirrra123 [75]

To solve this problem it is necessary to address the concepts related to Torque as a function of the force and distance where it is applied and the moment of inertia from which the torque, moment of inertia and angular acceleration are related.

By definition the torque is defined as

\tau = F*r

Where,

\tau = Torque

F = Force

r = Radius

For our values we have:

\tau = F*r

\tau = (1.75*10^3)(2.8*10^{-2})

\tau = 49Nm

Consequently the calculation of the moment of inertia would then be given by the relationship

\tau = I\alpha

I=\frac{\tau}{\alpha}

Replacing with our values

I = \frac{49}{150}

I = 0.322Kg.m^2

The moment of inertia of the boxer's forearm 0.322Kg.m^2

4 0
3 years ago
A 2N and 6N force pull on an object to the right and a 4N force pulls to the left a 0.5kg object. What is the net force on the o
Angelina_Jolie [31]

Explanation:

F net = 2+6-4 ( 2 and 6 N are in same direction so they get added, 4N in opposite direction so it will be subtracted)

F net=4 N

3 0
3 years ago
Two spectators at a soccer game in Montjuic Stadium see, and a moment later hear, the ball being kicked on the playing field. Th
Akimi4 [234]

Answer:

a) The distance of spectator A to the player is 79.2 m

b) The distance of spectator B to the player is 43.9 m

c) The distance between the two spectators is 90.6 m

Explanation:

a) Knowing the time it takes the sound to reach both spectators, we can calculate their position relative to the player, using this equation:

x = v * t

where:

x = position of the spectators

v = speed of sound

t = time

Then, the position for spectator A relative to the player is:

x = 343 m/s * 0.231 s = 79.2 m

b)For spectator B:

x = 343 m/s * 0.128 s

x = 43.9 m

The distance of spectator A and B to the player is 79.2 m and 43.9 m respectively.

c) To calculate the distance between the spectators, please see the attached figure. Notice that the distance between the spectators is the hypotenuse of the triangle formed by the sightline of both. We already know the longitude of the two sides. Then, using Pythagoras theorem:

(Distance AB)² = A² + B²

(Distance AB)² = (79.2 m)² + (43.9 m)²

Distance AB = 90. 6 m

6 0
4 years ago
A stone with a weight of 5.29 N is launched vertically from ground level with an initial speed of 26.0 m/s, and the air drag on
makkiz [27]

Answer:

a) 19.4 m/s

b) 19 m/s

Explanation:

a) In the given question,

the potential energy at the initial point = Ui = 0

the potential energy at the final point = Uf = mgh

the kinetic energy at the initial point = Ki = 1/2 mv₀².

the kinetic energy at the final point = Kf = 0

work done by air= Ea= fh =  0.262 N

Now, using the law of conservation of energy

initial energy= final energy

Ki +Ui = Kf + Uf +Ea

1/2 mv₀² + 0 = 0 + mgh + fh

1/2 mv₀² = mgh + fh

h = v₀²/ 2g (1 +f/w)

calculate m

m= w/g = 5.29 /9.8

= 0.54 kg

h = 20 ²/ (2 x9.80) x (1 0.265/5.29)

h = 19.4 m.

b) 1/2 mv² + 2fh = 1/2 mv₀²

Vg = 19 m/s

6 0
3 years ago
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