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3 years ago

explain how the composition of a star that will form a billon years in the future will differ the composition of our sun.

Physics

1 answer:

Grace [21]3 years ago

3 0

Answer:

Explanation:

Basically the star slowly burns its hydrogen into Helium. Depending on the mass, the star will have a turbulent core where the Helium will be fully mixed or a radiative core where the helium will settle at the centre (remember it's heavier than Hydrogen). The second case is what happens in the Sun.

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A scientist begins with 100 milligrams of a radioactive substance that decays exponentially. After 33 hours, 50 mg of the substa

Hoochie [10]

Answer:

$m\approx34.99$

Explanation:

Radioactive decay behaves according to the law of exponential decay:

$m(t)=m_0*e^{-rt}$

Where:

$r=Decay\hspace{3}rate$

$t=Time(In\hspace{3}days)$

$m_0=Initial\hspace{3}amount\hspace{3}of\hspace{3}substance$

$m(t)=Amount\hspace{3}of\hspace{3}substance\hspace{3}at\hspace{3}time\hspace{3}t$

So we need to find the decay rate r. Let's find it using the equation and the data provide, but first, we need to convert the hours in days:

$50h*\frac{1day}{24h}=\frac{25}{12}day\\ 33h*\frac{1day}{24h} =\frac{11}{8}day$

Now for $t=\frac{11}{8},m=50$ then:

$m(\frac{11}{8} )=100*e^{-r(\frac{11}{8}) } =50$

Divide both sides by 100:

$e^{-r(\frac{11}{8}) } =\frac{1}{2}$

Take the natural logarithm of both sides:

$-\frac{11}{8}x=ln(\frac{1}{2} )$

Multiply both sides by -8/11:

$x=\frac{-8ln(\frac{1}{2} )}{11} \approx0.504107$

Now we have found the rate decay r, let's find how many milligrams will remain after 59 hours (25/12 day):

$m(\frac{25}{12} )=100*e^{-0.504107*\frac{25}{12}) } =100*e^{-1.050222917}=34.98597508\approx35.99$

4 0

3 years ago

A ball is dropped off a very tall canyon ledge.

oksano4ka [1.4K]

Answer:

V = 49.05 [m/s]

Explanation:

We can easily find the result using kinematics equations, first, we will find the distance traveled during the 5 seconds.

$y =y_{o}+(v_{o}*t)+(\frac{1}{2}*g*t^{2} )$

where:

Yo = initial position = 0

y = final position [m]

Vo = initial velocity = 0

t = time = 5 [s]

g = gravity aceleration = 9.81 [m/s^2]

The initial speed is zero, as the body drops without imparting an initial speed. Therefore:

y = 0 + (0*5) + (0.5*9.81*5^2)

y = 122.625[m]

Now using the following equation we can find the speed it reaches during the 5 seconds.

$v_{f} ^{2}= v_{i} ^{2}+(2*g*y)\\v_{f}=\sqrt{2*9.81*122.625} \\v_{f}=49.05 [m/s]$

6 0

4 years ago

What is the motion of the particles in this kind of wave? A hand holds the left end of a set of waves. The waves themselves make

almond37 [142]

Answer:

Explanation:

The particles will move side to side over large areas

6 0

3 years ago

Sound waves are also called compression waves. This means that as the wave travels through air, the ________ increases and decre

Nuetrik [128]

I believe the answer is pressure. hope this helps

3 0

3 years ago

PLEASE HURRY!!!

lidiya [134]

Answer:

The difference between the lower mantle and the oceanic crust is first their respective locations, pressure and temperature-- the pressure and temperature increases with depth in the earth this the mantle is more hot and under great pressure than the crust.

Explanation:

8 0

3 years ago

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