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olga2289 [7]
2 years ago
15

SIMPLIFY- working on algebra -x-4x

Mathematics
1 answer:
blsea [12.9K]2 years ago
5 0

Answer:

The correct answer is,

- 5x

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Select the equation that is equivalent to the equation: y+6=-4(X-2)
USPshnik [31]
First, you gotta distribute the -4 to x-2, 

<span>y+6=-4(X-2)
y+6=-4x+8

Then, subtract both sides by 6,
y+6-6=-4x+8-6
y=-4x+2

Done</span>
7 0
3 years ago
Read 2 more answers
Solve 3x − 2y = −21 and 2x + 5y = 5 using elimination
nydimaria [60]

Answer:

x = -5 and y = 3

Step-by-step explanation:

There are two equations :

3x − 2y = −21 ....(1)

2x + 5y = 5 ......(2)

Multiply equation (1) by 2 and equation (2) by 3.

6x - 4y = -42 ...(3)

6x + 15y = 15 ....(4)

Subtract equation (4) from (3) :

6x - 4y - (6x + 15y) = -42 -15

-4y -15y = -57

-19y = -57

y = 3

Put y = 3 in equation (2) :

2x + 5(3) = 5

2x = 5-15

2x = -10

x = -5

So, the value of x is (-5) and y = 3.

6 0
2 years ago
If Jay ran 1 mile in 10 minutes on Monday, 2 miles in 20 minutes on Tuesday,
earnstyle [38]

Answer:

4 miles

Step-by-step explanation:

5 0
3 years ago
The Dot plot shows the salaries for the employees that two small companies before a new company head is hired on each company se
Dmitry_Shevchenko [17]

Answer:

D

Step-by-step explanation:

8 0
2 years ago
Researchers fed mice a specific amount of Dieldrin, a poisonous pesticide, and studied their nervous systems to find out why Die
Elodia [21]

Answer:

Step-by-step explanation:

Part A

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

6 0
3 years ago
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