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antiseptic1488 [7]

3 years ago

9

Neptune is 4.5 billion kilometers from the sun. Represent this number in scientific notation

2 answers:

denis-greek [22]3 years ago

7 0

Answer:

4.5*10^9

Step-by-step explanation:

Tanya [424]3 years ago

5 0

Answer:

4.5 x 10 ^9

Step-by-step explanation:

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1.23 x 1.1 equals =

Snowcat [4.5K]

Answer:

1.23 x 1.1 = 1.32

3 0

2 years ago

NEED UR HELPPPP PLEASE..

Mashcka [7]

17.32 deal with it aaaaaaaaaaaaaaaaa

8 0

3 years ago

Read 2 more answers

Solve 7.8e^((x/3)ln(5))=14. What are the exact and approximate solutions?

Dimas [21]

$\bold{\text{Answer}:\quad x=3\bigg(\dfrac{ln\frac{14}{7.8}}{ln(5)}\bigg)=1.09}$

<u>Step-by-step explanation:</u>

$7.8e^{\frac{x}{3}\cdot ln(5)}=14\\\\\\e^{\frac{x}{3}\cdot ln(5)}=\dfrac{14}{7.8}\\\\\\ln\bigg(e^{\frac{x}{3}\cdot ln(5)}\bigg)=ln\bigg(\dfrac{14}{7.8}\bigg)\\\\\\\frac{x}{3}}\cdot ln(5)=ln\bigg(\dfrac{14}{7.8}\bigg)\\\\\\\large\boxed{x=3\bigg(\dfrac{ln\frac{14}{7.8}}{ln(5)}\bigg)}\\$

x ≈ 1.09

6 0

3 years ago

A book has a front and a back and 400 pages. The front and back cover are each 0.9mm thick measured to 1 decimal place. Each pag

zhuklara [117]

The minimum thickness of the book would simply be the sum of the thickness of the two cover pages and all the pages in between. That is:

minimum thickness = 0.9 mm * 2 + 0.13 mm * 400

<span>minimum thickness = 53.8 mm</span>

3 0

3 years ago

A spinner has equal regions numbered 1 through 20. What is the probability that the spinner will stop on an odd number or a mult

klio [65]

Answer:

<em>Probability that the spinner will stop on an odd number or a multiple of 5 is </em><em>0.6</em>

Step-by-step explanation:

Probability = $\frac{Required outcomes}{Total possible outcomes}$

We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20

<em>Total possible outcomes: 20</em>

<em>Outcomes that spinner will stop on an odd number, n(Odd): 10</em>

1, 3, 5, 7, 9, 11, 13, 15, 17, 19

Probability of spinner stoping on Odd number:

P(Odd) = $\frac{n(Odd)}{Total}$ = $\frac{10}{20}$ = $\frac{1}{2}$ = 0.5

Outcomes that spinner will stop on a multiple of 5, n(5): 4

5, 10, 15, 20

Probability of spinner stoping on multiple of 5:

P(5) = $\frac{n(5)}{Total}$ = $\frac{4}{20}$ = $\frac{1}{5}$ = 0.2

Odd numbers which are a multiple of 5 are: 5 and 15

So,

P(Odd and 5) = $\frac{2}{20}=\frac{1}{10}=0.1$

Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:

P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6

7 0

3 years ago