Answer:
A) F=-20.16×10⁹N
B) if the distance doubles, force is 4 times smaller.
Explanation:
q1=-28C
q2=5mC=0.005C
d=25cm=0.25m
Electrostatic force between charges: F=k×q1×q2/d², where k is a coefficient that has the value k=9 × 10⁹ N⋅m²⋅C^(-2) for air.
Thus:
F=9×10⁹×(-28)×0.005/0.25²
F=-20.16×10⁹N
The minus sign indicates attraction.
If distance doubles, d1=2×d, then we have 4d² at the denominator and the force is 4 times smaller.
They will rise to the 2nd layer of the atmosphere where the temperature decreases by a lot and then they will blow up
Here
- Acceleration and initial velocities are constant.
According to first equation of kinematics.
- Time was t at velocity v
- Time will be 4t at velocity 4v
Answer:
17.7 m/s
Explanation:
Given:
y₀ = 0 m
y = 16 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: v
v² = v₀² + 2a (y − y₀)
v² = (0 m/s)² + 2 (9.8 m/s²) (16 m − 0 m)
v = 17.7 m/s
The ball is moving at a speed of 17.7 m/s when it hits the ground.
Answer:
a) 3.0×10⁸ m
b) 0 m
Explanation:
Displacement is the distance from the starting position to the final position.
a) In half a year, the Earth travels from one point on the circle to the point on the exact opposite side of the circle (from 0° to 180°). The distance between the points is the diameter of the circle.
x = 2r
x = 2 (1.5×10⁸ m)
x = 3.0×10⁸ m
b) In a full year, the Earth travels one full revolution, so it ends up back where it started. The displacement is therefore 0 m.
