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serious [3.7K]
4 years ago
7

Interactive LearningWare 22.2 reviews the fundamental approach in problems such as this. A constant magnetic field passes throug

h a single rectangular loop whose dimensions are 0.46 m x 0.68 m. The magnetic field has a magnitude of 3.0 T and is inclined at an angle of 67o with respect to the normal to the plane of the loop. (a) If the magnetic field decreases to zero in a time of 0.49 s, what is the magnitude of the average emf induced in the loop
Physics
1 answer:
inessss [21]4 years ago
7 0

Explanation:

The dimension of a single rectangular loop is 0.46 m x 0.68 m.

Magnetic field, B = 3 T

The loop is inclined at an angle of 67 degrees with respect to the normal to the plane of the loop.

It is required to find the magnitude of the average emf induced in the loop if the magnetic field decreases to zero in a time of 0.49 s.

Te induced emf in the loop is given by :

\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(BA)}{dt}\\\\\epsilon=A\dfrac{dB}{dt}\cos\theta\\\\\epsilon=0.46\times 0.68\times \dfrac{3}{0.49}\times \cos(67)\\\\\epsilon=0.74\ V

So, the magnitude of the average emf induced in the loop is 0.74 V.

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At what value of angle between two vectors will the resultant of the two vectors be maximum?
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The resultant is maximum when the angle between the two vectors is zero

Explanation:

The formula to calculate the resultant of two vectors A, B is the following:

R=\sqrt{A^2+B^2+2ABcos \theta}

where

A is the magnitude of vector A

B is the magnitude of vector B

\theta is the angle between the directions of A and B

This formula can be derived by applying the parallelogram law.

From the formula, we observe that:

- When \theta=0^{\circ} (vectors A and B parallel), cos \theta = 1. so the resultant becomes simply

R=\sqrt{A^2+B^2 + 2AB}=\sqrt{(A+B)^2}=A+B

- When \theta = 90^{\circ} (vectors A and B perpendicular), cos \theta = 0, so the resultant becomes

R=\sqrt{A^2+B^2}

- When \theta=180^{\circ} (vectors A and B anti-parallel), cos \theta = -1, so the resultant becomes

R=\sqrt{A^2+B^2 - 2AB}=\sqrt{(A-B)^2}=|A-B|

By looking at the three cases and at the formula, we see that the maximum value of the resultant is when the angle between the two vectors is zero, since in that case the resultant is simply obtained by adding the magnitudes of the two vectors.

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

3 0
4 years ago
All living organisms reproduce by a live functioning baby leaving the mother's body.​
algol13

Answer:

there is no question

Explanation:

4 0
3 years ago
Squids are the fastest marine invertebrates, using a powerful set of muscles to take in and then eject water in a form of jet pr
tatuchka [14]

Answer:

0.25 m/s

Explanation:

This problem can be solved by using the law of conservation of momentum - the total momentum of the squid-water system must be conserved.

Initially, the squid and the water are at rest, so the total momentum is zero:

p_i = 0

After the squid ejects the water, the total momentum is

p_f = m_s v_s + m_w v_w

where

m_s = 1.60 kg is the mass of the squid

v_s is the velocity of the squid

m_2 = 0.115 kg is the mass of the water

v_w = 3.50 m/s is the velocity of the water

Due to the conservation of momentum,

p_i = p_f

so

0=m_s v_s + m_w v_w

so we can find the final velocity of the squid:

v_s = -\frac{m_w v_w}{m_s}=-\frac{(0.115 kg)(3.50 m/s)}{1.60 kg}=-0.25 m/s

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3 years ago
Which can lead scientists to change a theory that has already been accepted? Check all that apply.
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3 years ago
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Vlad1618 [11]

Answer:

a) 16m/s b) 192m

Explanation:

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b) v2^2=v1^2 + 2ad

rearranging

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v2^2-v1^2/2= a d

v2^2-v1^2/2a=d

16m/s^2 - 32m/s^2/ 2 x-2m/s^2 =d

d=192m

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3 years ago
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