Question

Three samples of wood with the same volume were weighed. Sample A has a mass of 224.96 g, sample B has a mass of 0.55632 Ibs, and sample C has a mass of 0.30648 kg. Which block of wood has the highest density? Show your work. 2.21 Ibs = 1 kg
Note: I have no idea how to solve this. Someone help me please!!!!

Answer 1

Answer:

sample C have the highest density

Explanation:

Data Given:

mass of sample A = 224.96 g

Convert g to kg

1 g = 0.001 Kg

224.96 g = 224.96 x 0.001 = 0.225 kg

mass of sample B = 0.55632 Ibs

Convert lbs to kg

2.21 lb = 1 kg

0.55632 Ibs = 0.55632 / 2 = 0.278 kg

mass of sample C = 0.30648 kg

Solution:

To calculate density of every sample we have the following formula

            d = m/v . . . . . . . . . . (1)

It is clear from the formula that density have direct relation with mass and inverse relation with volume, that is density increase with increasing in mass.

As we have same volume of wood sample, so suppose that each sample have volume of  2 cm³

So now we find density for each sample

As for sample A

• mass of sample A = 0.225 kg

• supposed volume = 2 cm³

Put values in formula 1

                d = 0.225 kg / 2 cm³

                d = 0.128 kg/cm³

As for sample B

• mass of sample A = 0.278 kg

• supposed volume = 2 cm³

Put values in formula 1

                d = 0.278 kg / 2 cm³

                d = 0.139 kg/cm³

As for sample C

• mass of sample C = 0.30648 kg

• supposed volume = 2 cm³

Put values in formula 1

                d = 0.30648 kg / 2 cm³

                d = 0.153 kg/cm³

So it shows that sample C have the highest density that is 0.153 kg/cm³ . As it have the highest mass too among all samples.