MO Diagram of C₂⁻ is shown below,
Bond order is calculated as,
Bond Order = [# of e⁻s in BMO]-[#of e⁻s in ABMO] / 2
Where,
BMO = Bonding Molecular Orbital
ABMO = Anti-Bonding Molecular Orbital
Putting values,
Bond Order = [9]-[4] / 2
Bond Order = 5 / 2
Bond Order = 2.5
Is ...,.,,,KG .....,.,.,.
It increases
The attractive force between the nucleus and the electrons INCREASES if the proton number increases while the number of energy levels remains constant.
Explanation:
Remember that protons carry a positive charge while electrons carry a negative charges. Unlike charges attract while like charges repel. An increase in the number of protons increases the positive charge of the atomic nucleus. This means that the force of attraction on the electron cloud of the atom increases.
This is why the atomic radius of atoms decreases across a period (from left to right) as the mass number of the atoms increase (while the number of electron orbitals remains the same across the period).
Learn More:
For more on the atomic radius check out;
brainly.com/question/13126562
brainly.com/question/1604565
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Answer:
The answer to your question is None, sulfur share of its electrons
Explanation:
Just remember:
Sulfur, S, has 6 electrons in its outermost shell
Hydrogen, H, has 1 electron in its outermost shell
Oxygen, O, has 6 electrons in its outermost shell
See the picture below
The electrons of sulfur are in blue
The electrons of oxygen are in red
The electron in hydrogen is in yellow
Sulfur is the central atom and it shares all its electrons with the oxygen.
