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Marina86 [1]
3 years ago
8

3. A student determined the Kf of t-butyl alcohol using tap water instead of distilled or deionized water. Describe the problems

that might have been encountered. How would theses problems affect the magnitude of Kf.
Physics
2 answers:
Neporo4naja [7]3 years ago
4 0

Answer:

The freezing point constant can be compromised by various causes, for example, the amount of solute that dissolves, its nature, and the amount of ions into which the solute can dissociate. The water that comes from the tap and that you could use to prepare the solutions contains various ions, such as fluoride ions, chloride ions, etc., which would not exist in distilled water. The presence of these ions previously causes the freezing point to decrease, therefore, using tap water in this experiment would increase the kf value (greater than the real one) for this system.

Explanation:

eduard3 years ago
3 0

Answer:

The Kf (Freezing Point Depression Constant) is been affect by freezing point among many other factor now using tap water for this experiment would mean that there would be salt present in the solution in that tap water is usually added fluoride which would react with the natural potassium present in the water to form a salt this salt would depress the freezing point of the water hence the value of Kf would be bigger that the actual value

Explanation:d

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A rocket is fired at 100 m/s at an angle of 37, how many seconds is it in the air?
Sonbull [250]

Answer:

12.3 seconds

Explanation:

time in air = 2(v)/g

2(100sin(37))/9.8

=12.28 seconds

7 0
3 years ago
A motorcycle starts from rest and has a constant acceleration. In a time interval t, it undergoes a displacement x and attains a
iren [92.7K]

Answer:

√(6ax)

Explanation:

Hi!

The question states that during a time t the motorcyle underwent a displacement x at constant acceleration a starting from rest, mathematically we can express it as:

x=(1/2)at^2

Then the we need to find the time t' for which the displacement is 3x

3x=(1/2)a(t')^2

Solving for t':

t'=√(6x/a)

Now, the velocity of the motorcycle as a function of time is:

v(t)=a*t

Evaluating at t=t'

v(t')=a*√(6x/a)=√(6*x*a)

Which is the final velocity

Have a nice day!

3 0
3 years ago
How did bohr propose light was emitted from a material?
Artemon [7]

Answer:

when an electron made a transition from an outer orbit to one closer to the nucleus

Explanation:

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6 0
2 years ago
An unknown material, m1 = 0.49 kg, at a temperature of T1 = 92 degrees C is added to a Dewer (an insulated container) which cont
erastova [34]

Answer:

c_u=1540.5J/kg^{\circ}K

Explanation:

We know that heat relates to mass, specific heat and variation of temperature experimented because of this heat through the equation Q=mc\Delta T=mc(T_f-T_i). The heat released by the unknown material is absorbed by water, so we have Q_u=-Q_w, and we can write:

m_uc_u(T_{uf}-T_{ui})=-m_wc_w(T_{wf}-T_{wi})

Since thermal equilibrium is reached we know that T_{cf}=T_{wf}=T_f=31^{\circ}C=304^{\circ}K, where we have added 273^{\circ} to convert the temperature from Celsius to Kelvin, as <em>we must do</em>. Since we want the specific heat of the unknown material, we do:

c_u=-\frac{m_wc_w(T_f-T_{wi})}{m_u(T_f-T_{ui})}

Which for our values is:

c_u=-\frac{(1.1kg)(4186J/kg^{\circ}K)((304^{\circ}K)-(294^{\circ}K))}{(0.49kg)((304^{\circ}K)-(365^{\circ}K))}=1540.5J/kg^{\circ}K

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3 years ago
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