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Marina86 [1]
2 years ago
8

3. A student determined the Kf of t-butyl alcohol using tap water instead of distilled or deionized water. Describe the problems

that might have been encountered. How would theses problems affect the magnitude of Kf.
Physics
2 answers:
Neporo4naja [7]2 years ago
4 0

Answer:

The freezing point constant can be compromised by various causes, for example, the amount of solute that dissolves, its nature, and the amount of ions into which the solute can dissociate. The water that comes from the tap and that you could use to prepare the solutions contains various ions, such as fluoride ions, chloride ions, etc., which would not exist in distilled water. The presence of these ions previously causes the freezing point to decrease, therefore, using tap water in this experiment would increase the kf value (greater than the real one) for this system.

Explanation:

eduard2 years ago
3 0

Answer:

The Kf (Freezing Point Depression Constant) is been affect by freezing point among many other factor now using tap water for this experiment would mean that there would be salt present in the solution in that tap water is usually added fluoride which would react with the natural potassium present in the water to form a salt this salt would depress the freezing point of the water hence the value of Kf would be bigger that the actual value

Explanation:d

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Leni [432]

Answer:

force

Explanation:

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5 0
3 years ago
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Suppose you want to calculate how much work it
Jobisdone [24]

Mass is not necessary the main thing we need is Displacement

As

  • W=FD

Or

  • Work done=Force×Displacement

The amount of work done is calculated as the force exerted to remove a object to D distance .

6 0
2 years ago
What quantity does the Hamiltonian correspond to? Rest mass Potential energy Total energy Kinetic energy Bohr frequency Lagrangi
PSYCHO15rus [73]

Answer:

The correct option is: Total energy

Explanation:

The Hamiltonian operator, in quantum mechanics, is an operator that is associated with the<u> total energy of the system.</u> It is equal to the sum of the total kinetic energy and the potential energy of all the particles of the system.

The Hamiltonian operator was named after the Irish mathematician, William Rowan Hamiltonis denoted and is denoted by H.

3 0
2 years ago
Based on Newton's law of motion, which combination of rocket bodies and engine will result in the acceleration of 40 m/s ^2 at t
ad-work [718]

The question is incomplete. The complete question is :

The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.

A 4-column table with 3 rows. The first column labeled Body has entries 1, 2, 3. The second column labeled Mass (grams) has entries 500, 1500, 750. The third column labeled Engine has entries 1, 2, 3. The fourth column labeled Force (Newtons) has entries 25, 20, 30.

Based on Newton’s laws of motion, which combination of rocket bodies and engines will result in the acceleration of 40 m/s2 at the start of the launch?

Body 3 + Engine 1

Body 2 + Engine 2

Body 1 + Engine 2

Body 1 + Engine 1

Solution :

Given :

Body       Mass (gram)     Engine      Force (newtons)

1                   500                 1                     25

2                  1500                2                    20

3                  750                  3                    30

The body 1 has a mass of 500 gram which is equal to 0.5 kg

And engine 2 has a force of 20 newtons.

We know that according to Newton's laws of motion,

Force = mass x acceleration

 20    = 0.5 x acceleration

Acceleration $=\frac{20}{0.5}$

                      $=\frac{200}{5}$

                      $= 40 \ m/s^2$

Therefore, based on laws of motion of Newton, the Body 1 + Engine 2 combination of the rocket bodies and engines will result in an acceleration of $ 40 \ m/s^2$ at the start of the launch.

8 0
3 years ago
Hooke's law describes a certain light spring of unstretched length 34.8 cm. When one end is attached to the top of a doorframe a
DaniilM [7]

Answer:

a) k = 1343.6\,\frac{N}{m}, b) l = 0.501\,m\,(50.1\,cm)

Explanation:

a) The Hooke's law states that spring force is directly proportional to change in length. That is to say:

F \propto \Delta l

In this case, the force is equal to the weight of the object:

F = m\cdot g

F = (8.22\,kg)\cdot (9.807\,\frac{m}{s^{2}} )

F = 80.614\,N

The spring constant is:

k = \frac{F}{\Delta l}

k = \frac{80.614\,N}{0.408\,m-0.348\,m}

k = 1343.6\,\frac{N}{m}

b) The length of the spring is:

F = k\cdot (l-l_{o})

l = l_{o} + \frac{F}{k}

l=0.348\,m+\frac{205\,N}{1343.6\,\frac{N}{m} }

l = 0.501\,m\,(50.1\,cm)

6 0
3 years ago
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