Draw the structures and provide the names of all the isomeric alcohols that have the molecular formula C4H10O Draw the structure
1 answer:
Answer:
Draw the structures and provide the names of all the isomeric alcohols that have the molecular formula C4H10O.
Draw the structures of (a) 6-methyl-3-heptanol and (b) trans-2-methylcyclohexanol
Explanation:
Isomers are compounds with the same molecular formula but different structural arrangements of atoms.
The given molecule is:
C4H10O.
The possible isomeric alcohols structures are shown below:
Structure of (a) 6-methyl-3-heptanol:
The root word -hept indicates that the main carbon chain has seven carbons.
-ol suffix indicates the presence of alcohol functional group at third carbon.
The 6-methyl prefix indicates the presence of methyl group as the substituent at the sixth position of the main carbon chain.
The structure of 6-methyl-3-heptanol is shown below:
The structure of trans-2-methyl cyclohexanol is shown below:
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Answer:
4.1x10⁻⁵
Explanation:
The dissociation of an acid is a reversible reaction, and, because of that, it has an equilibrium constant, Ka. For a generic acid (HA), the dissociation happens by:
HA ⇄ H⁺ + A⁻
So, if x moles of the acid dissociates, x moles of H⁺ and x moles of A⁻ is formed. the percent of dissociation of the acid is:
% = (dissociated/total)*100%
4.4% = (x/[HA])*100%
But x = [A⁻], so:
[A⁻]/[HA] = 0.044
The pH of the acid can be calcualted by the Handersson-Halsebach equation:
pH = pKa + log[A⁻]/[HA]
3.03 = pKa + log 0.044
pKa = 3.03 - log 0.044
pKa = 4.39
pKa = -logKa
logKa = -pKa
Ka =
Ka =
Ka = 4.1x10⁻⁵