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3 years ago

Suppose HIJK is a parallelogram. Find the value of x and y.

Mathematics

2 answers:

Kryger [21]3 years ago

6 0

Answer:

x = 90, y = 12

Step-by-step explanation:

The key to this problem is the fact that <u>opposite sides of a parallelogram are congruent</u> (their lengths are equal).

Set up and solve two equations, one for x and one for y.

x + 80 = 2x - 10

80 = x - 10

90 = x

--------------------------

3y - 4 = y + 20

2y - 4 = 20

2y = 24

y = 12

solmaris [256]3 years ago

5 0

Answer is x= 90 y=12

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The table shows the percent of adults who used computers from 1984

MrMuchimi

Answer:

3.1 (nearest tenth)

Step-by-step explanation:

Year (independent variable) = x

Percent of adults (dependent variable) = y

Rate of change is given as = $\frac{y_2 - y_1}{x_2 - x_1}$ .

Let,

$(1989, 20) = (x_1, y_1)$

$(2007, 76) = (x_2, y_2)$

Plug in the values into the equation

Rate of change = $\frac{76 - 20}{2007 - 1989}$

Rate of change = $\frac{56}{18} = 3.1$ (nearest tenth)

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3 years ago

What is the Y and x intercept of 9X-6Y= 72

11Alexandr11 [23.1K]

Answer: The y-intercept is -12

The x-intercept is 8

Step-by-step explanation: Factor out 3

Divide all by 3 to simplify.

9x - 6y = 72 is equivalent to

3x - 2y = 24

At this point, you can substitute 0 for x and solve for y

3(0) -2y = 24. -2y/-2 = 24/-2

y = -12

And substitute 0 for y and solve for x.

3x -2(0) = 24. 3x/3 = 24/3

x = 8

OR Change to slope intercept form:

y = mx + b. b is the y intercept.

-2y = -3x + 24. Solve for y.

Divide all by-2

y = 3x/2 - 12.

The y-intercept is -12

To find the x-intercept, substitute 0 for y and solve for x.

0 = 3x/2 -12 Add 12 to both sides.

12 = 3x/2. Multiply both sides by 2/3

8 = x

The x-intercept is 8

7 0

3 years ago

How do you get the square root of 100000

finlep [7]

The square root would be 316

6 0

3 years ago

The equation t^3=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A

ankoles [38]

Answer:

2√2

Step-by-step explanation:

We can find the relationship of interest by solving the given equation for A, the mean distance.

<h3>Solve for A</h3>

$T^3=A^2\\\\A=\sqrt{T^3}=T\sqrt{T}\qquad\text{take the square root}$

<h3>Substitute values</h3>

The mean distance of planet X is found in terms of its period to be ...

$D_x=T_x\sqrt{T_x}$

The mean distance of planet Y can be found using the given relation ...

$T_y=2T_x\\\\D_y=T_y\sqrt{T_y}=2T_x\sqrt{2T_x}=(2\sqrt{2})T_x\sqrt{T_x}\\\\D_y=2\sqrt{2}\cdot D_x$

The mean distance of planet Y is increased from that of planet X by the factor ...

2√2

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2 years ago

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Marrrta [24]

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3 years ago