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harkovskaia [24]
3 years ago
7

Nellie budgeted $50 per day for food costs. If these are costs for the two

Mathematics
1 answer:
VashaNatasha [74]3 years ago
7 0
12.98+18.95=31.93 50-31.93= 18.07. $18.07 for her dinner
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He ate 0.1 times as much dog food on Wednesday as he ate on Tuesday. If her dog ate 6 cups of dog food on Tuesday, how much did
Sveta_85 [38]

Answer:

6.6 cups of dog food

Step-by-step explanation:

6x0.1=.6

6+.6=6.6

4 0
3 years ago
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Which measurement is most accurate to describe the amount a coffee cup could hold 350 mL 2.4 L 25 mL or 0.8 L
katrin [286]
The answer would probably be 25mL
4 0
3 years ago
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Which are correct representations of the inequality 6x ≥ 3 + 4(2x – 1)? Check all that apply.
Verdich [7]

Answer:

6x ≥ 3 + 4(2x - 1)

⇔ 6x ≥ 3 + 8x - 4        => remove the parentheses

⇔ 6x - 8x ≥ 3 - 4

⇔ -2x ≥ -1

⇔ 2x ≤ 1 (or 1 ≥ 2x)

⇔ x ≤ 1/2

⇔ x ≤ 0.5

The answer for the question should be:

1 ≥ 2x

6x ≥ 3 + 8x – 4

and the first graph.

6 0
3 years ago
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Mean for 16, 12, 13, 22
pishuonlain [190]

Answer:

mean = sum of the terms/total no. of terms

mean = (16+12+13+22)/4

mean = 63/4 or 15.75

6 0
3 years ago
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Answer this question please; number 5... show all work thank you
My name is Ann [436]

Answer:

rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour

Step-by-step explanation:

We will make a table of the trip there and back using the formula distance = rate x time

                 d              =            r       x       t

there

back

The distance there and back is 264 miles, so we can split that in half and put each half under d:

               d            =         r        x        t

there    132

back     132

It tells us that the trip there is with the wind and the trip back is against the wind:

           

              d           =        r         x        t

there     132        =    (r + w)

back      132       =     (r - w)

Finally, the trip there took 3 hours and the trip back took 6:

           

             d         =        r        *        t

there    132     =    (r + w)     *       3

back     132     =    (r - w)      *       6

There's the table.  Using the distance formula we have 2 equations that result from that info:

132 = 3(r + w)        and        132 = 6(r - w)

We are looking to solve for both r and w.  We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:

132 = 3r + 3w and

132 - 3w = 3r so

44 - w = r.  Subbing that into the second equation:

132 = 6(44 - w) - 6w and

132 = 264 - 6w - 6w and

-132 = -12w so

w = 11

Subbing w in to solve for r:

132 = 3r + 3(11) and

132 = 3r + 33 so

99 = 3r and

r = 33

7 0
3 years ago
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