An empirical research method in which data are gathered from observations of phenomena, hypothesis are formulated and tested, an
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Both aluminum and chlorine have known charges, which are +3 and -1 respectively. To make them cancel each other out in charge, you would need 3 chlorine and for one aluminum, therefore 
would be correct
Answer:
Following are the answer to this question:
Explanation:
The value of pH solution is =5.17 So, the p^{OH}:
=14-56.17
=8.823
The volume of the = 40.00 ml
convert into the liter= 0.040L
The value of the concentrated =0.10 M
The volume of the = 50.00 ml
convert into the liter= 0.050L
The value of concentrated = 0.10 M
The volume of the = 30 ml
convert into the liter= 0.030L
The value of concentrated =0.05 M
Calculating total volume=(0.40+0.050+0.030)
=0.120 L
calculating the new concentrated value of =
calculating the new concentrated value of =
calculating the new concentrated value of
when 1 mol
produced 2 mols
so, 0.0125 in
produced:
create the ICE table:
I (m) 0.033(m) 0.025 0.04166
C -0.025 -0.025 + 0.025
E 8.3\times 10^{-3} 0 0.0667
now calculating pH:
when ph= 8.83: