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AVprozaik [17]
3 years ago
11

300,000,000 m/s is the speed of ?

Chemistry
1 answer:
mariarad [96]3 years ago
7 0

Answer:

671080887.616

Explanation:

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Which type of heat exchanger shell and tube or plate heat exchanger is suitable for evaporation?
klasskru [66]

Answer:

shell and tube type heat exchanger

Explanation:

for evaporation the shell and tube type heat exchanger is best suited.

  • in the plate heat exchanger there is gaskets in between every part so this part become weak part in heat echanger and there is possibilities of leakage through this part, there is no such problem in shell and tube type.
  • the plate type cant be used when there is high temperature and high pressure drop but shell and tube type can be used
  • in evaporation there the liquids change into vapors due to which there is sudden change in pressure and in which plate type is not used because there is chances of leakage
5 0
3 years ago
The C2-C3 single bond in butane freely rotates at room temperature, see equation (1) below. In contrast, the C2-C3 single bond i
Murrr4er [49]

Answer: Rotation occurs at single bonds that are sigma bonds. Rotational barrier is the amount of  activation energy required to covert rotamer to another by rotation that occurs around the sigma bond(C-C single bond). Due to the presence of steric hindrance that is the nonbonding interaction effects the reactivity of ions and molecules, activation energy increases. So the rotational barrier in butenyl cation is high.

8 0
4 years ago
if the side if a chemical equation has 3, carbon atoms, 6 oxygen atoms and 4 hydrogen atoms then the right side of the chemical
DochEvi [55]
The right side will also have 3 carbon, 6 oxygen, and 4 hydrogen atoms. the atoms may come together to form a compound but it doesn't lose any atoms. Hope it helped!
6 0
3 years ago
When of a certain molecular compound X are dissolved in of benzene , the freezing point of the solution is measured to be . Calc
puteri [66]

The question is incomplete. Here is the complete question.

When 2.10 g of a certain molecular compound X are dissolved in 65.0 g of benzene (C₆H₆), the freezing point of the solution is measured to be 3.5°C. Calculate the molar mass of X. If you need any additional information on benzene, use only what you find in the ALEKS Data resource. Also, be sure your answer has a unit symbol, and is rounded to 2 significant digits.

Answer: MM = 47.30 g/mol.

Explanation: There is a relationship between <u>freezing</u> <u>point</u> <u>depression</u> and <u>molality</u>. With this last one, is possible to calculate <u>molar</u> <u>mass</u> or molar weight of a compound.

<u>Freezing</u> <u>Point</u> <u>Depression</u> occurs when a solute is added to a solvent: the freezing point of the solvent decreases when a non-volatile solute is incremented.

<u>Molality</u> or <u>molal</u> <u>concentration</u> is a quantity of solute dissolved in a certain mass, in kg, of solvent. Its symbol is m and it's defined as

m=\frac{moles(solute)}{kg(solvent)}

Freezing point depression and molal are related as the following:

\Delta T_{f}=K_{f}.m

where

\Delta T_{f} is freezing point depression of solution

K_{f} is molal freezing point depression constant

m is molality

Now, to determine molar mass, first, find molality of the mixture:

\Delta T_{f}=K_{f}.m

m=\frac{\Delta T_{f}}{K_{f}}

For benzene, constant is 5.12°C/molal. Then

m=\frac{3.5}{5.12}

m = 0.683 molal

Second, knowing the relationship between molal and moles of solute, determine the last one:

m=\frac{moles(solute)}{kg(solvent)}

mol(solute)=m.kg(solvent)

mol(solute) = 0.683(0.065)

mol(solute) = 0.044 mol

The definition for <u>Molar</u> <u>mass</u> is the mass in grams of 1 mol of substance:

n(moles)=\frac{m(g)}{MM(g/mol)}

MM=\frac{m}{n}

In the mixture, there are 0.044 moles of X, so its molecular mass is

MM=\frac{2.1}{0.044}

MM = 47.30 g/mol

The molecular compound X has molecular mass of 47.30 g/mol.

7 0
4 years ago
PLEASE HELP MEEEEEEE
Sliva [168]
Amount of copper= mass / molar mass = 17/64=0.2656
According to the balance equation, amount of hydrogen gas : amount of copper = 1:1
Therefore amount of hydrogen gas is 1:1
Thus mass of hydrogen gas is molar mass x mol= 1 x 0.2656= 0.266g
3 0
3 years ago
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