Firstly we need to determine the partial pressure of O2:
We will now use the Henry's Law equation to determine the solubility of the gas:
Answer: Solubility is 2.7x10^-3 M
Answer:
The correct statement is:
E - The entropy of the products is greater than the entropy of the reactants.
Explanation:
C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O
As glucose is a large molecule and then it is transformed into many molecules of water and carbon dioxide, the entropy of the system increases. If the number of molecules increases, the disorder increases.
Initial state: 7 molecules (1 glucose + 6 oxygen)
Final state: 12 molecules (6 carbon dioxide + 6 water)
Answer:
70 mL of 5% HCl and 30 mL of 15% HCl
Explanation:
We will designate x to be the fraction of the final solution that is composed of 5% HCl, and y to be the fraction of the final solution that is composed of 15% HCl. Since the percentage of the final solution is 8%, we can write the following expression:
5x + 15y = 8
Since x and y are fractions of a total, they must equal one:
x + y = 1
This is a system of two equations with two unknowns. We will proceed to solve for x. First, an expression for y is found:
y = 1 - x
This expression is substituted into the first equation and we solve for x.
5x + 15(1 - x) = 8
5x+ 15 - 15x = 8
-10x = -7
x = 7/10 = 0.7
We then calculate the value of y:
y = 1 - x = 1 - 0.7 = 0.3
Thus 0.7 of the 100 mL will be the 5% HCl solution, so the volume of 5% HCl we need is:
(100 mL)(0.7) = 70 mL
Similarly, the volume of 15% HCl we need is:
(100 mL)(0.3) = 30 mL
Answer:
The new pressure is 0.5 atm
Explanation:
Step 1: Data given
Volume of oxygen = 300 mL = 0.300 L
Pressure = 1.00 atm
Temperature = 300 K
The volume increases to 1000mL = 1.00 L
The temperature increases to 500 K
Step 2: Calculate the new pressure
(P1*V1)/T1 = (P2*V2)/T2
⇒with P1 = the initial pressure = 1.00 atm
⇒with V1 = the initial volume = 0.300 L
⇒with T1 = the initial temperature = 300 K
⇒with P2 = the new pressure = TO BE DETERMINED
⇒with V2 = the increased volume = 1.00 L
⇒with T2 = the increased temperature = 500 K
(1.00 atm* 0.300 L)/300 K = (P2 * 1.00L) / 500 K
P2 = (1.00 *0.300 * 500) / (300 *1.00)
P2 = 0.5 atm
The new pressure is 0.5 atm
This impurity is troubling from an economic standpoint because it lead to decrease in the yield of phosphorus
- Ferrophosphorus is a byproduct of phosphorus production in submerged-arc furnaces , by their reduction with carbon. It is formed from the iron oxide impurities.
- Iron impurities present in the calcium phosphate will be precipitated out as the iron phosphate which eventually will lead to the decrease in the yield of phosphorous during the production of phosphorous.
Thus we can conclude that Fe₂P causes decrease in yield
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