Question

The sum of two numbers is 73. Twice the smaller number is one less than the larger number. The smaller number is

Answer 1

Answer:

The big number is 41 and the small number is 32.

Step-by-step explanation:

b + s = 73

2b - s = 50        Add these equations together

3b = 123            Divide both sides by 3

b = 41

Now plug this into the first equation to find s

41 + s = 73

-41       - 41

s = 32