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STALIN [3.7K]
3 years ago
7

Help me please I have to finish this by tonight

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0

Answer:

a=13 b=13

Step-by-step explanation:

Because the triangles are congruent, their corresponding angles will be congruent, too.

So, ∠Y≅∠S  and ∠Z≅∠T.

Set the values of these angles equal to each other and solve.

∠Y≅∠S               ∠Z≅∠T

4a-4= 48                5b-3= 62

4a=52                    5b= 65

a=13                        b= 13

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8 0
3 years ago
An earthquake with a magnitude of about 2. 0 or less is called a microearthquake. It is not usually felt. The intensity of an ea
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The intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of an a standard earthquake .

<h3>What is magnitude of earthquake?</h3>

Magnitude of earthquake is the measure of the size of origin of the earthquake. The magnitude of the earthquake keeps the same value for each place.

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8 0
3 years ago
What are the endpoint coordinates for the mid segment of △PQR that is parallel to PQ?
diamong [38]

Answer:

So the end points of the mid segment are:

S(-3.5,0.5)

T(-1,-0.5)

Step-by-step explanation:

First of all we need to list the co-ordinates of the points of the triangle shown.

P\rightarrow(-3,3)

Q\rightarrow(2,1)

R\rightarrow(-4,-2)

We need to find mid segment of the triangle which is parallel to segment PQ. This would mean we need to find midpoints of segment PR and QR and then join the points to get mid segment.

Midpoint Formula:

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Midpoint of PR:

S((\frac{-3+(-4)}{2},\frac{3+(-2)}{2})\\\\(\frac{-3-4}{2},\frac{3-2}{2})\\\\(\frac{-7}{2},\frac{1}{2} )

S(-3.5,0.5)

Midpoint of QR:

T(\frac{2+(-4)}{2},\frac{1+(-2)}{2})\\\\(\frac{2-4}{2},\frac{1-2}{2} )\\\\(\frac{-2}{2},\frac{-1}{2}

T(-1,-0.5)

So the end points of the mid segment are:

S(-3.5,0.5)

T(-1,-0.5)

By mid segment theorem we know that the line joining midpoints of two sides of a triangle is parallel to the 3rd side.

∴ We know ST is parallel to PQ  

4 0
3 years ago
Read 2 more answers
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