Answer: Tmelt = 19.89mins
Explanation: (complete question- 334×10^3j/kg. How much time, Tmelt passes before the ice starts to melt?)
For ice to melt, its temperature must be 0* C.
Let
Q1 = heat required to raise the ice temp from -16.1 °C. to 0* C.
Q2 = heat required to melt the ice
Q1 = MCp(delta T)
Q2 = m(Hf)
where
M = mass of the ice = 0.500 kg (given)
Cp = specific heat of ice = 2100 J/kg K (given)
delta T = temperature change = 0 - -16.1= 16.1 °C.
Hf = heat of fusion of ice = 334 x 10^3 J/jg.
Substituting values,
Q1 = 0.500× 2100× 16.1 = 16905J
Q2 = 0.500 × 334×10^3 = 167,000J
Heat required to melt the ice = Q1 + Q2 = 16905 + 167000 = 183905 J
How much time Tmelts = Q1/ 850 = 16905/850 = 19.89mins.
