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Black_prince [1.1K]
2 years ago
13

A test specimen in a tensile test has a gage length of 2.0 in and an area = 0.5in^2. During the test the specimen yields under a

load of 32,000 lb. The corresponding gage length = 2.0083 in. This is the 0.2% yield point. The maximum load of 60,000 lb is reached at a gage length = 2.6 in. Determine a) yield strength, b) madulus of elasticity, and c) ten
Physics
1 answer:
VladimirAG [237]2 years ago
7 0

Answer:

yield strength is 64000 lb/ in²

modulus of elasticity is 29.76 ×10^{6} lb/in²

Explanation:

given data

length L = 2 in

area A = 0.5 in²

load = 32000 lb

gage length L1 = 2.0083 in

yield point = 0.2%

maximum load = 60000 lb

to find out

yield strength and modulus of elasticity

solution

we apply here yield strength that is express as

yield strength = \frac{load}{area}  ...........1

yield strength =  \frac{32000}{0.5}

yield strength = 64000 lb/ in²

and

modulus of elasticity  is calculated as

modulus of elasticity =  \frac{yield strength}{strain}    ..........2

here strain = \frac{L1 - L}{L}  

strain = \frac{2.0083 - 2}{2}  

strain = 0.00415

so new strain after offset is here 0.00415 - 0.002

new strain = 0.00215

so from equation 2

modulus of elasticity =  \frac{yield strength}{strain}  

modulus of elasticity =  \frac{64000}{0.00215}  

modulus of elasticity is 29.76 ×10^{6} lb/in²

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Graphic attached

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