<u>Answer:</u> The Young's modulus for the wire is 
<u>Explanation:</u>
Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.
The equation representing Young's Modulus is:

where,
Y = Young's Modulus
F = force exerted by the weight  = 
m = mass of the ball = 10 kg
g = acceleration due to gravity = 
l = length of wire  = 2.6 m
A = area of cross section  = 
r = radius of the wire =  (Conversion factor:  1 m = 1000 mm)
      (Conversion factor:  1 m = 1000 mm)
 = change in length  = 1.99 mm =
 = change in length  = 1.99 mm = 
Putting values in above equation, we get:

Hence, the Young's modulus for the wire is 
 
        
             
        
        
        
<u>Answer</u>
The combined displacement is 2km north
<u>Explanation</u>
Since displacement is a vector quantity, we take into account the direction.
Good for us all the displacement vectors are in the same dimension, so we can make north positive and south negative or vice-versa.
We now add to obtain,

This will simplify to

Therefore the combined displacement is 2km north
 
        
             
        
        
        
Gravity is the correct answer.
 
        
             
        
        
        
Answer:
N = 337.96 N
Explanation:
∅ = 32º
F = 249 N
m = 21 Kg
N = ?
We can apply:
∑ F = 0  (↑)
- Fy - W + N = 0   ⇒    N = Fy + W
⇒  F*Sin ∅ + m*g = N
⇒  N = (249 N*Sin32º) + (21 Kg*9.81 m/s²)
⇒  N = 337.96 N  (↑)