Answer:
Work done = 125π J
Explanation:
Given:
P = P_i * ( 1 - (x/d)^2 / 25)
d = 5.0 cm
x = 5 * d cm = 25d
Pi = 12 bar
Work done = integral ( F . dx )
F (x) = P(x) * A
F (x) = (πd^2 / 4) * P_i * (1 - (x/d)^2 / 25)
Work done = integral ((πd^2 / 4) * P_i * (1 - (x/d)^2 / 25) ) . dx
For Limits 0 < x < 5d
Work done = (πd^2 / 4) * P_i integral ( (1 - (x/d)^2) / 25)) . dx
Integrate the function wrt x
Work done = (πd^2 / 4) * P_i * ( x - d*(x/d)^3 / 75 )
Evaluate Limits 0 < x < 5d :
Work done = (πd^2 / 4) * P_i * (5d - 5d / 3)
Work done = (πd^2 / 4) * P_i * (10*d / 3)
Work done = (5 π / 6)d^3 * P_i
Input the values:
Work done = (5 π / 6)(0.05)^3 * (1.2*10^6)
Work done = 125π J
Answer:
Explanation:
Bandwidth is the difference between the upper and lower frequencies in a continuous set of frequencies. The bandwidth may be determined by use of the following formula:
Hence the signal’s frequency bandwidth is:
Answer:
209.55 ft
Explanation:
Given Data:
Benchmark:
Reduced Level or Elevation = 210.50
Height of Instrument = Reduced Level + Back sight Reading
Height of Instrument = 210.50 + 3.57 = 214.07 ft
Turning Point:
Back sight Reading = 2.91 ft
Fore Sight Reading = 4.52
Reduced Level or Elevation of Turning Point = Height of Instrument – fore sight Reading
Reduced Level or Elevation of Turning Point = 214.07 – 4.52 = 209.55 ft
Height of Instrument at Turning Point = Reduced Level + Back sight Reading
Height of Instrument at Turning Point = 209.55 + 2.91 = 212.46 ft
Idk what that means i’m sorry
Answer:
Plumbing using a one-way check valve to stop water flowing back on a pump when the pump shuts off.
Explanation:
Diodes are like check valves, keeping current from flowing both ways. Used to create d.c. out of a.c by rectification. Also to block flow if d.c. power like a battery is hooked up in reverse polarity.