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MatroZZZ [7]
3 years ago
10

Technician A says a ground return can be hard-wired to the battery negative. Technician B says a component cannot be chassis-gro

unded through the metal frame of the vehicle. Who is correct?
Engineering
1 answer:
Tems11 [23]3 years ago
4 0
Technician A

explanation: self explanatory
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A 1,040 N force is recorded on a hemispherical vane as it redirects a 2.5 cm- blade diameter water jet through a 180 angle. Dete
Alex777 [14]

This question is incomplete, the complete question is;

A 1,040 N force is recorded on a hemispherical vane as it redirects a 2.5 cm- blade diameter water jet through a 180 angle.

Determine the velocity of the flowing water jet if the blade is assumed to be frictionless.

Answer: the velocity of the flowing water jet is 32.55 m/s  assuming the blade is frictionless

Explanation:

Given that;

Force Ft = 1040 N

diameter d = 2.5 cm = 0.025 m

we know that; force acting on Hemispherical plate is;

Ft = 2δav²

where

a is area = π/4(0.025)²

δ is density of water = 1000 kg/m³

v is velocity = ?

now we substitute

1040 = 2 × 1000 × (π/4(0.025)²) × v²

1040 =  0.9817v²

v² = 1040 / 0.9817

v² = 1059.3867

v = √1059.3867

v = 32.5482 ≈ 32.55 m/s

Therefore the velocity of the flowing water jet is 32.55 m/s  assuming the blade is frictionless

8 0
3 years ago
Aspectos de las técnicas escultóricas
mel-nik [20]
Técnicas y materiales de escultura
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Esculpir. ...
Talla de madera. ...
Talla de marfil. ...
Piedras semipreciosas y tallas de conchas. ...
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Decoración.


Corrígeme si estoy equivocada.. :)
3 0
3 years ago
A 200-L tank (see Fig. P4.107) initially contains water at 100 kPa and a quality of 1%. Heat is transferred to the water, thereb
Tomtit [17]

Answer:

25.46 MJ

Explanation:

continuity : m3 - m1 = -m<em>e</em>

<em>Energy Equation: m3u3 - m1u1 = -meue + 1Q3</em>

<em />

<em>See the image attached (Well typed out format)</em>

5 0
4 years ago
Write down the types of the Hydraulic Cylinders?
nirvana33 [79]

Answer:

There are following type of hydraulic cylinders

1.Single acting

2.Double acting

3.Single acting spring loaded

4.Non differential type

5.Ram type

6.Piston type

7.Actuating type

8.Telescopic type

4 0
4 years ago
The A-36 steel pipe has a 6061-T6 aluminum core. It issubjected to a tensile force of 200 kN. Determine the averagenormal stress
sasho [114]

Answer:

In the steel: 815 kPa

In the aluminum: 270 kPa

Explanation:

The steel pipe will have a section of:

A1 = π/4 * (D^2 - d^2)

A1 = π/4 * (0.8^2 - 0.7^2) = 0.1178 m^2

The aluminum core:

A2 = π/4 * d^2

A2 = π/4 * 0.7^2 = 0.3848 m^2

The parts will have a certain stiffness:

k = E * A/l

We don't know their length, so we can consider this as stiffness per unit of length

k = E * A

For the steel pipe:

E = 210 GPa (for steel)

k1 = 210*10^9 * 0.1178 = 2.47*10^10 N

For the aluminum:

E = 70 GPa

k2 = 70*10^9 * 0.3848 = 2.69*10^10 N

Hooke's law:

Δd = f / k

Since we are using stiffness per unit of length we use stretching per unit of length:

ε = f / k

When the force is distributed between both materials will stretch the same length:

f = f1 + f2

f1 / k1 = f2/ k2

Replacing:

f1 = f - f2

(f - f2) / k1 = f2 / k2

f/k1 - f2/k1 = f2/k2

f/k1 = f2 * (1/k2 + 1/k1)

f2 = (f/k1) / (1/k2 + 1/k1)

f2 = (200000/2.47*10^10) / (1/2.69*10^10 + 1/2.47*10^10) = 104000 N = 104 KN

f1 = 200 - 104 = 96 kN

Then we calculate the stresses:

σ1 = f1/A1 = 96000 / 0.1178 = 815000 Pa = 815 kPa

σ2 = f2/A2 = 104000 / 0.3848 = 270000 Pa = 270 kPa

5 0
3 years ago
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