Which of the following is not a step in a building’s life cycle?

Race cars at the Indianapolis Speedway average speeds of 185 mi/h. After determining the altitude of Indianapolis, find the Mach

denis23 [38]

Answer:

- the Mach number is 0.24.

- Compressibility becomes effective when Mach number is greater than 0.3, the Mach number of the race cars is less than 0.3, hence, compressibility will not affect their aerodynamics.

Explanation:

Given the data in the question;

Average speed V = 185 miles per hour = ( 185 /2.237 ) m/s = 82.7 m/s

From Almanac, we can find that Indianapolis is at 220 m altitude.

So from table, at that altitude, the standard speed of sound will be 339.4 m/s .

Mach number of the race car will be;

Mach Number = Velocity / sound speed

we substitute

Mach Number = ( 82.7 m/s ) / ( 339.4 m/s )

Mach Number = 0.24

Therefore the Mach number is 0.24.

We know that, compressibility becomes effective when the Mach number is greater than 0.3.

Since the Mach number of the race cars is less than 0.3, compressibility will not affect their aerodynamics.

8 0

3 years ago

A rotating cup viscometer has an inner cylinder diameter of 2.00 in., and the gap between cups is 0.2 in. The inner cylinder len

Lesechka [4]

Answer:

The dynamic viscosity and kinematic viscosity are $1.3374\times 10^{-6}$ lb-s/in2 and $1.4012\times 10^{-3}$ in2/s.

Explanation:

Step1

Given:

Inner diameter is 2.00 in.

Gap between cups is 0.2 in.

Length of the cylinder is 2.5 in.

Rotation of cylinder is 10 rev/min.

Torque is 0.00011 in-lbf.

Density of the fluid is 850 kg/m3 or 0.00095444 slog/in³.

Step2

Calculation:

Tangential force is calculated as follows:

T= Fr

$0.00011 = F\times(\frac{2}{2})$

F = 0.00011 lb.

Step3

Tangential velocity is calculated as follows:

$V=\omega r$

$V=(\frac{2\pi N}{60})r$

$V=(\frac{2\pi \times10}{60})\times1$

V=1.0472 in/s.

Step4

Apply Newton’s law of viscosity for dynamic viscosity as follows:

$F=\mu A\frac{V}{y}$

$F=\mu (\pi dl)\frac{V}{y}$

$0.00011=\mu (\pi\times2\times2.5)\frac{1.0472}{0.2}$

$\mu =1.3374\times 10^{-6}$ lb-s/in².

Step5

Kinematic viscosity is calculated as follows:

$\upsilon=\frac{\mu}{\rho}$

$\upsilon=\frac{1.3374\times 10^{-6}}{0.00095444}$

$\upsilon=1.4012\times 10^{-3}$ in2/s.

Thus, the dynamic viscosity and kinematic viscosity are $1.3374\times 10^{-6}$ lb-s/in2 and $1.4012\times 10^{-3}$ in2/s.

4 0

4 years ago

A rigid, sealed cylinder initially contains 100 lbm of water at 70 °F and atmospheric pressure. Determine: a) the volume of the

soldier1979 [14.2K]

Answer:

Determine A) The Volume Of The Tank (ft^3) Later A Pump Is Used To Extract ... A rigid, sealed cylinder initially contains 100 lbm of water at 70 degrees F and atmospheric pressure. ... Later a pump is used to extract 10 lbm of water from the cylinder. The water remaining in the cylinder eventually reaches thermal equilibrium ...

3 0

3 years ago

How do I draw this from the side?

tangare [24]

Answer:

draw it 3D

Explanation:

because it's a 3D picture

6 0

3 years ago

For a fluid with a Prandtl Number of 1000.0, the hydrodynamic layer is thinner than the thermal boundary layers. a) True b) Fals

kvv77 [185]