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sveta [45]
3 years ago
5

Brittle failure is a type of failure in which: (a) There is large amount of plastic deformation (b) Large amount of elastic defo

rmation (c) Very little plastic and elastic deformation (d) None of the above
Engineering
1 answer:
sp2606 [1]3 years ago
7 0

Answer:

    c). Very little plastic and elastic deformation

Explanation:

Brittle failure is a sudden, very rapid crack where there is no sign of any plastic deformation or ductility. The failure is not stable unlike ductile failure and the the crack propagates very fast without any further increase of any stress. In brittle failure there is very little plastic deformation and low energy is absorbed before fracture takes place.

Thus, very little plastic and elastic deformation takes place in brittle failure.

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3 years ago
Make a list of common uses of pneumatic systems in engineering contexts. Explain how each system functions and what benefit it b
MArishka [77]

Answer:

Bicycle Pumps. These pumps are used to inflate bicycle wheels, basketballs, footballs, Ect. Brakes on Buses and Trucks. Tire Pressure Gauges. Jackhammer. Pneumatic Nail Guns.

Explanation:

8 0
2 years ago
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How many numbers multiple of 3 are in the range [2,2000]?
Alekssandra [29.7K]
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6 0
3 years ago
(a) The room-temperature electrical conductivity of a semiconductor specimen is 13 (Ω-m)-1. The hole concentration is known to b
Aleksandr-060686 [28]

Answer: a) 0.24E+20 m-3. b) p-type extrinsic.

Explanation:

The current density in a semiconductor is composed by two types of charge carriers: electrons and holes.

This parameter, is proportional to the Electric field within the semiconductor, being the proportionality constant, the electrical conductivity of the material, that takes into account the charge carrier concentrations, and the mobility for each type.

The expression for electrical conductivity is as follows:

σ = q . ne . µe  + q . np . µp  

Replacing by the given values, and the value of q (charge of an electron), we can get the only unknown that remains, ne , as follows:

ne =( σ – (q . np . µp)) / q µe = (13 (Ω.m)-1 – (1.6E-19) coul(4.0E+20) m-3.0.18) m2/V-s /( (1.6E-19).0.38) coul.m2/V-s

ne = 0.24E+20.

As ne is smaller than np, this means that the semiconductor behaves like a p-type extrinsic one.

7 0
3 years ago
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