Answer:
This a pure case of conflict of interests between the interest of the shareholders who are the original owners of the company and management's interest in earning much more,even if it at the expense of the shareholders.
Explanation:
Management is the entrusted with the day to day affairs of corporations.In carrying out their duty,they must have at the back of their minds that maximization of shareholder's wealth is of top priority.
However.some management teams in a bid to gain undue advantage set their remuneration below reasonable levels.
Ultimately,when this happens, their duty to watch over the investment of shareholders clashes with their interest for personal gains.
1350kgm/s
Explanation:
Given parameters:
Mass of Sam = 75kg
Velocity = 18m/s
Unknown:
Momentum = ?
Solution:
Momentum is the property of a moving body with respect to its mass and velocity.
Objects in motion have momentum. The more the velocity of a body, the more its momentum. Also, the more the mass of an object, the more momentum it possess.
Momentum is a function of the mass and the velocity of a body
Momentum = mass x velocity
Momentum = 75 x 18 = 1350kgm/s
learn more:
Conservation of momentum brainly.com/question/2990238
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The total work done on the car is 784Joule.
<h3>What's the acceleration of the car?</h3>
- As per Newton's equation of motion, V= U+at
- U= initial velocity= 0 m/s
V= vinal velocity= 20m/s
t= time = 10s
a= acceleration
=> a= 20/10= 2m/s²
<h3>What's the distance covered by the car in 10 seconds?</h3>
- As per Newton's equation of motion,
V²-U² = 2aS
- S= distance covered by the car
- So, 20²-0=2×2×S=4S
=> 400= 4S
=> S= 400/4= 100m
<h3>What's the work done on the car due to frictional force?</h3>
Work done by frictional force= frictional force × distance
= (0.2×4×9.8)×100
= 784Joule
Thus, we can conclude that the work done on the car is 784Joule.
Learn more about the work done here:
brainly.com/question/25573309
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Taiga is the answer.
Hope it helps!
The student who did the most work is student 2 with 2500 Joules.
<u>Given the following data:</u>
To determine which of the students did the most work:
Mathematically, the work done by an object is given by the formula;
<u>For </u><u>student 1</u><u>:</u>
Work done = 600 Joules
<u>For </u><u>student 2</u><u>:</u>
Work done = 2500 Joules.
Therefore, the student who did the most work is student 2 with 2500 Joules.
Read more: Read more: brainly.com/question/13818347
