Given data:
Volume of calcite (V) = 15 cm³,
mass of calcite (m) = 40.5 g,
find the
density of calcite (ρ) = ?
density is defined as " it is the amount of matter of an object in a given volume". Simply it is the ratio of matter in an object to its volume. The unit of density is kg/m³ in SI system or g/cm³ in CGS system.
Mathematically,
density ( ρ) = mass/volume
= m/V g/cm³
= 40.5 g/15 cm³
= 2.7 g/cm³
Hence, the density of calcite is <em>2.7 g/cm³ </em>
The four qualifications for the presidency are outlined in the constitution.
Answer
given,
mass of the stick = 290 grams = 0.29 Kg
Force on the stick on one side = F = 9 N
force acting perpendicular to stick.
magnitude of acceleration
rate of change of angular momentum is equal to Force
rate of change of angular momentum = 9 N
F = m a
![a = \dfrac{F}{m}](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7BF%7D%7Bm%7D)
![a = \dfrac{9}{0.29}](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7B9%7D%7B0.29%7D)
a = 31.034 m/s²
Direction of motion will in the direction of force application or in the direction of change of velocity
Answer:
<h2>The water tank have to support a pressure of 50,456 Pa.</h2>
Explanation:
To design the cylindrical, pressurised water tank, we need to calculate the total pressure that it's being applied to tank, in order to know how strong we need to make it.
The total pressure (P) on the tank is always the sum of all pressures that are involved, external air pressure (P1), inside pressure (P2) and the pressure due to the mass of water (P3).
So, The external air pressure (P1) is 95.0 kPa.
The inside pressure (P2) is 110 kPa.
The pressure due to the mass of water (P3) will be calculated with:
; where p is density of the water, g is the gravity and h the height.
Using the values given g = 3.71 m/s2; h = 13.6 m and p = 1000 kg/m3.
![P_{3}=(1000\frac{kg}{m^{3} } )(3.71\frac{m}{s^{2} } )(13.6m) = 50,456 Pa.](https://tex.z-dn.net/?f=P_%7B3%7D%3D%281000%5Cfrac%7Bkg%7D%7Bm%5E%7B3%7D%20%7D%20%20%29%283.71%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D%20%29%2813.6m%29%20%3D%2050%2C456%20Pa.)
Therefore, we need to design an water tank strong enough to endure a pressure of 50,456 Pa.
I don’t know but I will figur it out