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Jlenok [28]
4 years ago
12

a bus accelerates at -0.5 m/s^2 for 12.5 seconds if the bus had an initial speed of 31 /s what is its new speed

Physics
2 answers:
Arlecino [84]4 years ago
8 0

Answer:

as the other person said, the answer is 24.75 m/s

Explanation:

aleksandr82 [10.1K]4 years ago
3 0
Vf=v0+at so 31m/s-.5m/s^2*12.5= 24.75m/s is the new speed. the negative sign is showing a deceleration.

Hope this helps! Please rate if you like my answer! Thank you!!
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A projectile is launched from the surface of a planet (mass = 15 x 1024 kg, radius = R = 9.6 x 106 m). What minimum launch speed
Serjik [45]

Answer:

The minimum launch speed is 13366.40 m/s.

Explanation:

Given that,

Mass of planet M=15\times10^{24}\ kg

Radius R= 9.6\times10^{6}\ m

Height = 6R

We need to calculate the speed

Using relation between gravitational force and total energy

-\dfrac{GMm}{6R+R}=\dfrac{1}{2}mv^2-\dfrac{GMm}{R}

\dfrac{}{}mv^2=\dfrac{GMm}{7R}-\dfrac{GMm}{R}

\dfrac{1}{2}mv^2=\dfrac{6GMm}{7R}

v^2=\dfrac{2\times6GM}{7R}

Put the value into the formula

v=\sqrt{\dfrac{2\times6\times6.67\times10^{-11}\times15\times10^{24}}{7\times9.6\times10^{6}}}

v=13366.40\ m/s

Hence, The minimum launch speed is 13366.40 m/s.

6 0
3 years ago
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For Part A, Sebastian decided to use the copper cylinder. How would the magnitude of his q and ∆H compare if he were to redo Par
Vitek1552 [10]

The magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

The given parameters;

  • <em>initial temperature of metals, =  </em>T_m<em />
  • <em>initial temperature of water, = </em>T_i<em> </em>
  • <em>specific heat capacity of copper, </em>C_p<em> = 0.385 J/g.K</em>
  • <em>specific heat capacity of aluminum, </em>C_A = 0.9 J/g.K
  • <em>both metals have equal mass = m</em>

The quantity of heat transferred by each metal is calculated as follows;

Q = mcΔt

<em>For</em><em> copper metal</em><em>, the quantity of heat transferred is calculated as</em>;

Q_p = (m_wc_w + m_pc_p)(T_m - T_i)\\\\Q_p = (T_m - T_i)(m_wc_w ) + (T_m - T_i)(m_pc_p)\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m_p(T_m - T_i)\\\\m_p = m\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m(T_m - T_i)\\\\let \ (T_m - T_i)(m_wc_w )  = Q_i, \ \ \ and \ let \ (T_m- T_i) = \Delta t\\\\Q_p = Q_i + 0.385m\Delta t

<em>The </em><em>change</em><em> in </em><em>heat </em><em>energy for </em><em>copper metal</em>;

\Delta H = Q_p - Q_i\\\\\Delta H = (Q_i + 0.385m \Delta t) - Q_i\\\\\Delta H = 0.385 m \Delta t

<em>For </em><em>aluminum metal</em><em>, the quantity of heat transferred is calculated as</em>;

Q_A = (m_wc_w + m_Ac_A)(T_m - T_i)\\\\Q_A = (T_m -T_i)(m_wc_w) + (T_m -T_i) (m_Ac_A)\\\\let \ (T_m -T_i)(m_wc_w)  = Q_i, \ and \ let (T_m - T_i) = \Delta t\\\\Q_A = Q_i \ + \ m_Ac_A\Delta t\\\\m_A = m\\\\Q_A = Q_i \ + \ 0.9m\Delta t

<em>The </em><em>change</em><em> in </em><em>heat </em><em>energy for </em><em>aluminum metal </em><em>;</em>

\Delta H = Q_A - Q_i\\\\\Delta H = (Q_i + 0.9m\Delta t) - Q_i\\\\\Delta H = 0.9m\Delta t

Thus, we can conclude that the magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

Learn more here:brainly.com/question/15345295

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3 years ago
You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between
Klio2033 [76]

Answer:

a) u=0.05602\ m.s^{-1}

b) u'=0.0169\ m.s^{-1}

Explanation:

Given:

mass of the ball, m=0.4\ kg

horizontal velocity of the ball, u=10\ m.s^{-1}

mass of the person, M=71\ kg

a)

<u>Using the law of  conservation of momentum:</u>

m.v=(M+m).u

0.4\times 10=(71+0.4)\times u

u=0.05602\ m.s^{-1}

b)

Given:

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Using conservation of momentum,

m.v+M.u=m.v'+M.u'

0.4\times10+71\times 0=0.4\times 7+71\times u'

u'=0.0169\ m.s^{-1}

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3 years ago
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Which of these statements best explains why models are used to study atoms? Atoms of all materials are not the same. Atoms canno
Fed [463]

Answer by YourHope:


Hi! :)


Which of these statements best explains why models are used to study atoms?


Atoms are too small to be examined in detail without a microscope!


Models help scientists to study atoms because atoms are extremely small and can't even be seen!


:)

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Answer:

i dont know this one

Explanation:

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